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never [62]
3 years ago
5

How much work is done when a 4.0-newton box is carried horizontally a distance of 2.0 meters at a constant velocity?

Physics
2 answers:
alisha [4.7K]3 years ago
8 0
The answer is 0.0J. that's what I found out after i turned it in then corrected it<span />
monitta3 years ago
4 0

Answer: Work done by the box will be 8 Joules.

Explanation:

Work done by a substance is the product of the force applied on it and the displacement of a substance.

Mathematically,

W=F.s

Where,

W = work done = ? J

F = Force applied = 4 N

s = displacement = 2 m

Putting values in above equation, we get:

W=4N\times 2m=8Nm=8J

Hence, work done by the box will be 8 Joules.

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Angel hits a ball with a ball. The action is the ball . What what is reaction force?
Mumz [18]

When Angel hits a ball with the ball. As the action is a ball as it is hitted. The reaction force is the force exerted on another ball.

Newton’s third law of motion describes the two forces, action and reaction forces. This states that for every action force, there is an equal and opposite reaction force.

As Angel hits a ball with another ball, the action is the ball as it is hit. The ball exerts a force on the ball. This is the action force. The ball exerts an equal and opposite force on the bat, which is known as the reaction force.

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5 0
2 years ago
What is the deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h? (such deceleration caused on
Wewaii [24]

The deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h is  252.52\ m/s^2.

The acceleration in opposite direction is known as the deceleration. Basically the deceleration is negative value of the acceleration since the negative sign depicts its opposite in direction.

The given data:

time, t = 1.1 s

initial speed, u = 1000 km/h = \frac{2500}{9}\ m/s

final speed, v = 0 m/s

So we will be using the equation of motion, that is,

v = u + at

\therefore 0=\frac{2500}{9} + a(1.1)

\Rightarrow a=-\frac{2500}{9(1.1)}

\therefore a = - 252.52 \ m/s^2

Hence , the deceleration of the rocket is  252.52\ m/s^2.

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6 0
2 years ago
A 2500‐kg vehicle traveling at 25 m/s can be stopped by gently applying the breaks for 20 seconds. What is the average force sup
katen-ka-za [31]
Momentum = (mass) x (speed)

Change in momentum = (force) x (time)

The initial momentum is (mass) x (speed) = 2500x 25 = 62,500 kg-m/s.

Since you want to <u>stop</u> the vehicle, that number is also the required <em>change</em>
in momentum ... you want the vehicle to wind up with zero momentum.

62,500 = (force) x (time) = 20 x force

Divide each side by 20 :

force = 62,500 / 20 = <em>3,125 newtons </em>
3 0
3 years ago
The heating of Venus led to a further release of ______ from its surface. With nowhere for the greenhouse gas to go, Venus ended
DiKsa [7]

Answer:

The answer would be B

Explanation:

The atmosphere of Venus traps in lots of what from the Sun, it is the hottest planet in our solar system because of this. CO2 is a greenhouse gas and traps in heat. So B would be your answer.

5 0
3 years ago
Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject materia
melisa1 [442]

Answer:

H_2 = 91.55 km

Explanation:

Gravity on the surface of planet is given as

g = \frac{GM}{R^2}

as we know that

M = 8.93 \times 10^{22} kg

R = 1821 km

now gravity on the planet is

g = \frac{(6.67 \times 10^{-11})(8.93 \times 10^{22})}{(1821 \times 10^3)^}

so we have

g = 1.8 m/s^2

now we know that

H_{max} = \frac{v^2}{2g}

so we will say

\frac{H_1}{H_2} = \frac{g_2}{g_1}

\frac{500}{H_2} = \frac{9.81}{1.8}

H_2 = 91.55 km

5 0
3 years ago
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