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natima [27]
3 years ago
9

The heating of Venus led to a further release of ______ from its surface. With nowhere for the greenhouse gas to go, Venus ended

up with a ________ greenhouse effect.
methane (CH4), large

carbon dioxide (CO2), runaway

water (H2O), runaway

carbon dioxide (CO2), small
Physics
1 answer:
DiKsa [7]3 years ago
5 0

Answer:

The answer would be B

Explanation:

The atmosphere of Venus traps in lots of what from the Sun, it is the hottest planet in our solar system because of this. CO2 is a greenhouse gas and traps in heat. So B would be your answer.

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When a 4.60-kg object is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.30 cm. (a) If
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Answer:

a) y = 0.0075 m

b) W = 1.569 J

Explanation:

See attachment for the solution

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A force of 8,480 N is applied to a cart to accelerate it at a rate of 26.5 m/s2. What is the mass of the cart?
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When blueshift occurs,the preceived frequency of the wave would be?​
LiRa [457]

Answer:

When blueshift happens, the perceived frequency of the wave would be higher than the actual frequency.

Explanation:

As the name suggests, when blueshift happens to electromagnetic waves, the frequency of the observed wave would shift towards the blue (high-frequency) end of the visible spectrum. Hence, there would be an increase to the apparent frequency of the wave.

Blueshifts happens when the source of the wave and the observer are moving closer towards one another.

Assume that the wave is of frequency f\; {\rm Hz} at the source. In other words, the source of the wave sends out a peak after every (1/f)\; {\text{seconds}}.

Assume that the distance between the observer and the source of the wave is fixed. It would then take a fixed amount of time for each peak from the source to reach the observer.

The source of this wave sends out a peak after each period of (1/f)\; {\text{seconds}}. It would appear to the observer that consecutive peaks arrive every (1/f)\; {\text{seconds}}\!. That would correspond to a frequency of f\; {\rm Hz}.

On the other hand, for a blueshift to be observed, the source of the wave needs to move towards the observer. Assume that the two are moving towards one another at a constant speed of v \; {\rm m \cdot s^{-1}}.

Again, the source of this wave would send out a peak after each period of (1/f)\; {\text{seconds}}. However, by the time the source sends out the second peak, the source would have been v \cdot (1 / f) \; { \rm m}= (v / f)\; {\rm m} closer to the observer then when the source sent out the first peak.

When compared to the first peak, the second peak would need to travel a slightly shorter distance before it reach the observer. Hence, from the perspective of the observer, the time difference between the first and the second peak would be shorter than (1/f)\; {\text{seconds}}. The observed frequency of this wave would be larger than the original f\; {\rm Hz}.

6 0
3 years ago
When comparing equal volumes of a stronger and weaker acid, what would be observed?
liraira [26]
If you are in plato the answer is B.
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