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lesantik [10]
3 years ago
12

Jenny wants to paint the ceiling of her restaurant. the ceiling is in the shape of a square. its side lengths are 44 feet. suppo

se each can of paint will cover 242 square feet. how many cans will she need to paint the ceiling?
Mathematics
1 answer:
inysia [295]3 years ago
8 0
First we need to find the square footage of her ceiling, since it's a square just multiply the side by the side: 44•44=1936. Now divide the square feet by how many feet each can can paint: 1936/242=8. Jenny would need exactly 8 cans of paint to paint her ceiling :)
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What if the value of x? show all work
alina1380 [7]
For this case we can make use of the Pythagorean theorem.
 We have then:
 (root (117)) ^ 2 = x ^ 2 + 6 ^ 2
 Clearing x we have:
 x ^ 2 = (root (117)) ^ 2 - 6 ^ 2
 Rewriting:
 x = root (117-36)
 x = root (81)
 x = 9
 Answer:
 
The value of x is given by:
 
x = 9 cm
4 0
3 years ago
5^-1 = blank * 5^4 find the missing factor
skad [1K]

Answer:

1/3125 or, 5^-5

Step-by-step explanation:

5^-1 = blank * 5^4

1/5/625= blank   or,     5^-1/5^4=blank

blank=1/3125               5^-5=blank

4 0
3 years ago
A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft
lakkis [162]

\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}

\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}

\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}

8 0
3 years ago
At what point on the curve y = 19 2x is the tangent line perpendicular to the line 20x 4y = 1?
Gennadij [26K]

The points are; (7/2, -1/2).

<h3>What is the given point?</h3>

Now the tangent line is given as;20x 4y = 1. When we rewrite it in the slope intercept form, we have the equation as; y = 1 - 20x/4 or y = 1/4 - 5x.

Then to obtain the slope of the curve we have; y = 19 - 2x

dy/dx = 2

Using the relation;

m1m2 = -1

m2 = -1/2

Hence;

y = 1/4 - 5(-1/2)

y = 1/4 + 5/2

y = 7/2

Thus the points are; (7/2, -1/2)

Learn more about normal curve:brainly.com/question/10664419

#SPJ4

7 0
2 years ago
Need help, please answer correctly for branliest!
Dmitry_Shevchenko [17]

Answer:

68 degrees

Step-by-step explanation:

90 - 22 = 68 degrees

when you see the square looking thing it indicated a right angle which is equal to 90 degrees :)

4 0
3 years ago
Read 2 more answers
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