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3 years ago

12

1. Having one password for all accounts is an easy way to remember passwords, but it will expose you to what risk?

2 answers:

HACTEHA [7]3 years ago

6 0

But the risk is that if a hacker guesses that one password, he will now your password to all the other websites.

lilavasa [31]3 years ago

6 0

If someone was to find out one of your passwords then they can easily guess the other ones because of that one they found out.

So if your Roblox game account passcode was ChrisPBacon and I guessed it and so was your gmail account I can go on your gmail and say "hmm, maybe it's the same as his roblox account code then I can gain access to all your private info leading to me if I was a bad person taking your id and private info.

I have all my passcodes diffrent personally. Or you can put 2-step on for extra security.

I hope I helped you lots!! :3

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Brian is finishing a meal at his favorite restaurant. The check shows that the cost of the food is $42. He adds a 15% tip to the

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Answer:

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Step-by-step explanation:

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3 years ago

What is 10.7+ 2 times <br> 30.9

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3 years ago

Which of the following is not equal to sin⁡(-230°)?

xenn [34]

From trigonometry we know that:

if $sin(\theta)=sin(\alpha)$

then, $\theta=n\pi+(-1)^n\alpha$ (where $n$ is an integer)

This can be rewritten in degrees as:

$\theta=n(180^{\circ})+(-1)^n\alpha$ .............(Equation 1)

Now, in our case, $\alpha=-230^{\circ}$

Therefore, (Equation 1) can be written as:

$\theta=n(180^{\circ})+(-1)^n(-230^{\circ})$ ..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of $\theta$ that match.

For n=2, (Equation 2) gives us: $\theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}$ .

Thus, $sin(230^{\circ})=sin(130^{\circ})$

Now, we know that: $-sin(-50^{\circ})=sin(50^{\circ})$

Let n=-1, then:

$\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}$

Thus, $sin(-230^{\circ})=-sin(-50^{\circ})$

Likewise, $sin(-230^{\circ})=sin(50^{\circ})$

Only the last option $sin(-50^{\circ})$ will never match $sin(-230^{\circ})$ because no integral value of $n$ will ever give $\theta=-50^{\circ}$

Thus the last option is the correct option.

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nignag [31]

84.39 is ya answer to the question

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4 years ago

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Studentka2010 [4]

Answer:3

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