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nignag [31]
3 years ago
8

How do you solve? 2.5 x 1/4=

Mathematics
1 answer:
lubasha [3.4K]3 years ago
4 0

here you go, hope this helps

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A long-distance phone company has a monthly fee of $7.95 and charges a rate of $0.05 per minute. Another long-distance company h
d1i1m1o1n [39]

Answer:

100 minutes

Step-by-step explanation:

Let the number of minutes required for the two Billings to be equal be x.

Now we write this in an equation form.

7.95 + 0.05x = 9.95 + 0.03x

0.05x - 0.03x = 9.95 - 7.95

0.02x = 2

x = 2/0.02 = 100 minutes

At the 100th minute, the amount of Billings would be equal

8 0
3 years ago
Brainliest to correct
GarryVolchara [31]

Answer:

27

Step-by-step explanation:

5 0
3 years ago
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Find the quotient. Use a model to help you divide
Marianna [84]

Answer:

Step-by-step explanation:

6.15/5=1.23

The answer is B.

6 0
3 years ago
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aliya0001 [1]

Answer:

I think it would be A

Step-by-step explanation:

6 0
3 years ago
Extreme cold and hot temperatures are known to affect the operation of electronic components. Winter is approaching and you are
Musya8 [376]

Answer:

A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

Test statistic(Z) = 2.31

P-value = 0.0104

Step-by-step explanation:

Step 1

Null hypothesis: The average damaging temperature of nine iPods is 5°F

Alternate hypothesis: The average damaging temperature of nine iPods differs from 5°F

Step 2

Mean=5°F, Sd=3, df=n-1=9-1=8

The t-value corresponding to 8 degrees of freedom and 95% confidence level (5% significance level) is 2.306

Confidence Interval(CI) = (mean + or - t×sd/√n)

CI = (5 + 2.306×3/√8) = 5 + 6.918/2.828= 5+2.45=7.45°F

CI = (5 - 2.306×3/√8) = 5-2.45 = 2.55°F

Z = (sample mean - population mean)/(sd÷√n) = (5-2.55)/(3÷√8) = 2.45/1.061 = 2.31

Step 3

Using the standard distribution table, the cumulative area to the left of Z = 2.31 is 0.9896

P-value = 1 - 0.9896 = 0.0104

Step 4

Conclusion: A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

7 0
3 years ago
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