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Vlada [557]
3 years ago
13

What is A = bh solve for h

Mathematics
1 answer:
Lostsunrise [7]3 years ago
7 0

Answer:

Since you havent left us much background we will make it a/b=h

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Bess [88]

Answer:

Bee

Step-by-step explanation:

Ya like jazz?

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3 years ago
Plz someone help I will mark brainlest diameter is 8.8 yd​
sweet [91]

Answer:

60.79 square yards.

Step-by-step explanation:

d = 2r; d = 8.8.

8.8 = 2r

r = 8.8 / 2

r = 4.4 yards.

Since we now have the radius, we can find the area of the circle, which can be found using πr^2, or 3.14 * r^2.

4.4^2 * 3.14 = 19.36 * 3.14 = 60.7904.

Since the question tells us to round to the nearest hundredth, our final answer will be 60.79 square yards.

Hope this helps!

5 0
3 years ago
If a diagram is unmarked, can you assume...
Rudik [331]
Both pairs of vertical angles<span> (four </span>angles<span> altogether) always sum to a full </span>angle<span>(360°). In the figure above, </span>an angle<span> from each pair of </span>vertical angles<span> are adjacent</span>angles<span> and are </span>supplementary<span> (add to 180°). For example, in the figure above, m∠JQL + m∠LQK = 180°.</span>
5 0
3 years ago
Read 2 more answers
If an aircraft is present in a certain area, a radar correctly registers its presence with probability 0.99. if it is not presen
pishuonlain [190]

Answer:

A) 0.005

B) 0.001

C)0.0495

Step-by-step explanation:

Let A be the event that an aircraft is present and let B be the event the radar registers its presence.. Thus;

P(A) = Probability that an aircraft is present

P(A') = Probability that an aircraft is not present

P(B) = Probability that the radar generates an alarm

P(B') = Probability that the radar doesn't generate an alarm

Thus from what we are given, we have;

P(A) = 0.05

P(A') = 0.95

P(B) = 0.99

P(B') = 0.01

P(B|A') = 0.1

A) Probability of a false alarm will be;

P(A' ∩ B) = P(A) × P(B|A')

P(A' ∩ B) = 0.05 × 0.1 = 0.005

B) probability of missed detection is;

0.1 × (1 - 0.99) = 0.001

C) probability that an aircraft is present given that the radar registers a presence will be;

P(A ∩ B) = P(A) × P(B)

P(A ∩ B) = 0.05 × 0.99

P(A ∩ B) = 0.0495

5 0
3 years ago
he blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 247.3 and a standard deviation of 6
Ulleksa [173]

Answer:

The approximate percentage of women with platelet counts within 3 standard deviations of the​ mean is 99.7%.

Step-by-step explanation:

We are given that the blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 247.3 and a standard deviation of 60.7.

Let X = <em>t</em><u><em>he blood platelet counts of a group of women</em></u>

The z-score probability distribution for the normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 247.3

           \sigma = standard deviation = 60.7

Now, according to the empirical rule;

  • 68% of the data values lie within one standard deviation of the mean.
  • 95% of the data values lie within two standard deviations of the mean.
  • 99.7% of the data values lie within three standard deviations of the mean.

Since it is stated that we have to calculate the approximate percentage of women with platelet counts within 3 standard deviations of the​ mean, or between 65.2 and 429.4, i.e;

         z-score for 65.2 =  \frac{X-\mu}{\sigma}

                                     =  \frac{65.2-247.3}{60.7}  = -3

         z-score for 429.4 =  \frac{X-\mu}{\sigma}

                                       =  \frac{429.4-247.3}{60.7}  = 3

So, it means that the approximate percentage of women with platelet counts within 3 standard deviations of the​ mean is 99.7%.

4 0
3 years ago
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