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horsena [70]
3 years ago
7

How much more is five ninth’s greater than 4 fifteenths

Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0
The answer is 3.46154
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Solve the following equations: <br> 5x-(x+2)^2=x^2-8+x
Blababa [14]

Answer:

x = √2 = 1.414

Step-by-step explanation:

5x-(x+2)^2=x^2-8+x

since (x+2)^2 = x^2 + 2(x)(2) + 2^2 = x^2 + 4x + 4

so

5x - (x^2 + 4x + 4) = x^2 + x - 8

-x^2 + x - 4 = x^2 + x - 8

x^2 + x^2 + x - x = -4 + 8

2x^2 = 4

x^2 = 2

x = √2 = 1.414

3 0
2 years ago
Read 2 more answers
I need help with 1,2,3,6
laila [671]
1. 84
2. 3.36
3. 7
6. 279
3 0
3 years ago
Jackie cut a piece of paper along its diagonal, as shown below, forming two triangles.
harina [27]

Answer:

B. The two dimensions are the same in the triangles as they were in the rectangle.

Step-by-step explanation:

Given

Initial Shape: Rectangle (Before cut)

Final Shape: Triangles (After cut)

<em>Note that this can be explained properly with the use of attachments</em>

See attachment 1 for Before Cut

Before Cut represent the full rectangle before Jackie cut the piece of paper.

Let H and B represent the height and base of the triangle

Given that the rectangle is cut diagonally, this means that the cutting starts and ends at the opposite edges of the rectangle

See attachment 2 for After Cut

After Cut represent the two triangles after cutting the rectangle

From the attachment, you'll observe that the dimension of the two triangles (Triangle 1 and Triangle 2) are the same as it is with the rectangle;

In other words, the two triangle have their heights as H and their bases as B.

Hence, it can concluded that the two dimensions are the same in the triangles as they were in the rectangle.

4 0
3 years ago
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Riley's mom has asked him to go to the
Ierofanga [76]

Answer:

4 dollars

Step-by-step explanation:

8 0
3 years ago
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Use long division to divide x^3+x^2-2x+14 by x+3
bekas [8.4K]

First, x^3=x^2\cdot x, and if we multiply x+3 by x^2 we get

x^3+3x^2

Subtracting this from the numerator gives a remainder of

-2x^2-2x+14

Next, -2x^2=-2x\cdot x, and if we multiply x+3 by -2x we have

-2x^2-6x

and subtracting this from the previous remainder, we end up with a new remainder of

4x+14

Next, 4x=4\cdot x, and if we multiply x+3 by 4 we get

4x+12

Subtracting from the previous remainder, we get a new remainder of

2

which contains no more factors of x, so we're done.

So,

\dfrac{x^3+x^2-2x+14}{x+3}=x^2-2x+4+\dfrac2{x+3}

8 0
3 years ago
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