Answer:
-4
Step-by-step explanation:
There are many methods to solve this system of equations.
I will use the elimination method.
First step:
Multiply the first equation by -2
2(2x-3y) = -14(-2)
-4x + 6y = 28
Multiply the second equation by 3 so you can eliminate the y term
3(3x-2y) = -6(3)
9x-6y = -18
Second step: Add the equations vertically(Basically adding like terms)
-4x+6y = 28
+
9x - 6y = -18
5x = 10
Third step: Solve for x
x = 2
Substitute the x-value into any of the original equation to get the y value
3(x) - 2y = -6
3(2) - 2y = -6
6 - 2y = -6 (Since we are solving for y, it will be isolated and we will move 6 to the other side)
-2y = -6 - 6(Moving 6 to the other side makes it negative)
Solve for y by dividing by -2
y = 6
So (x, y) = (2, 6)
Since the question is asking to subtract x and y
2-6 = -4
Step-by-step explanation:
y = x² - 3x + 6
y = 2x + 6
y = y
x² - 3x + 6 = 2x + 6
x² - 5x = 0
x(x - 5) = 0
x = 0 and x = 5
y = 2x + 6 and y = 2x + 6
y = 2(0) + 6 and y = 2(5) + 6
y = 0 + 6 and y = 10 + 6
y = 6 and y = 16
(x1,y1) and (x2, y2) = (0,6) and (5,16)
Option → A
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Hope this helped!
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Let x represent the side length of the square end, and let d represent the dimension that is the sum of length and girth. Then the volume V is given by
V = x²(d -4x)
Volume will be maximized when the derivative of V is zero.
dV/dx = 0 = -12x² +2dx
0 = -2x(6x -d)
This has solutions
x = 0, x = d/6
a) The largest possible volume is
(d/6)²(d -4d/6) = 2(d/6)³
= 2(108 in/6)³ = 11,664 in³
b) The dimensions of the package with largest volume are
d/6 = 18 inches square by
d -4d/6 = d/3 = 36 inches long
Answer: 22
Step-by-step explanation:
To get from 59 to 51 you subtract 8 then it was minus 7, then minus 6, then minus 5, and then it just kept going down like that
