Answer:
2030
Explanation:
The computation of the total number of new generators including this year is shown below
Given that
(A) = 100
Common Ratio (r) = 1.15
n = 10
Now
Sum of 10 terms Sn is
= A × (r n - 1) ÷ (r - 1)
= 100 × (1.1510 - 1) ÷ (1.15 - 1)
= 100 × 3.0456 ÷ 0.15
= 2030
We simply applied the above formula so that the total number of new generators could come
Answer:
Explanation:
The journal entry is shown below:
(a) Factory Labor/Expenses A/c Dr $103,800
To Factory wages payable $91,000
To Employer payroll taxes payable $7,700
To Fringe benefits payable $5,100
(Being labor expenses are recorded)
(b) Direct labor A/c Dr $87192 ($103,800 × 84%)
Indirect labor A/c Dr $16,608 ($103,800 × 16%)
To Factory Labor $103,800
(Being factor labor is assigned)
Answer:
A fixed asset register is a detailed list of all fixed assets which are owned by a business. Its main purpose is to enable an organization to accurately record and maintain both financial and non-financial information pertaining to each asset and to easily identify and verify an asset when required.
Explanation:
Answer:
The correct answer is option b.
Explanation:
Inflation refers to the continuous and sustained growth in the general price level. As the price level rises, it reduces the purchasing power or value of cash balances held by the consumers to reduce. This causes real income to decline.
A certain level of inflation is desirable in an economy to promote growth but a high rate of inflation is harmful. Inflation can be of several types such as
- Demand-pull inflation
- Cost-push inflation
There are several measures used to calculate inflation, for instance, the consumer price index. To correct inflationary pressures, a government uses contractionary fiscal and monetary policy.
Answer:
Explanation:
S/N Age range Adult Population Population Internet Users
A 18 - 29 478 454
B 30 - 49 833 741
C 50 and above 1644 1058
Total 2955 2253
a) Let E = Estimate proportion and A = Internet users
Hence, n(E) = 478 and n(A) = 454
∴ Probability of Internet users (18 - 29), P(A) = n(A)/n(E) = 454/478 = 0.9498 (94.98%)
b) n(E) = 833 and n(B) = 741
∴ Probability of Internet users (30 - 49), P(B) = n(A)/n(E) = 741/833 = 0.8896 (88.96%)
c) n(E) = 1644 and n(C) = 1058
∴ Probability of Internet users (50 and above), P(C) = n(C)/n(E) = 1058/1644 = 0.6436 (64.36%)
d) Let Et = Total estimate proportion
Hence, n(Et) = 2955 and n(A) = 454
∴ Probability of 18 - 29 age range using Internet overall Pt(A) = n(A)/n(Et) = 454/2955 = 0.1536 (15.36%)
