<span>jogs
north for exactly 5.0 min at an average speed of 8.0 km/h.
Convert velocity from km/h to km/min
V = 8.0 km/h * 1h/60min = 2/15 km/min
Distance = V*t = [2/15 km/min]*5min = 2/3 km
He continues
north at a speed of 12.0 km/h for the next 30.0 min.
Again convert km/h to km/min
V = 12.0 km/h * 1h/60min = 1/5 km/min
D = V*t = [1/5 km/min]*30min = 6 km
He then turns
around and jogs south at a speed of 15.0 km/h for 15.0 min.
Position before turning around
X = 2/3 km + 6 km = 20/3 km North
D = V*t = 15.0 km/h *(1/4 h) = 15/4 km
New position: 20/3 km North - 15/4 km South = 35/12 km North
Then he jogs
south for another 20.0 min at 8.0 km/h.
D = V*t = 8.0km/h * [1/3 h] = 8/3 km
New position 35/12 km North - 8/3 km South = 3/12 = 1/4 km North
Total distance jooged = 20/3 km + 15/4 + 8/3 km = 157/12 km = 13.08 km ≈ 13.1 km
He walks the rest of the way
home
He will have to walk 1/4 km = 0.25 km to get home after he finishes jogging
</span>
Answer:
There are three ways an object can accelerate: a change in velocity, a change in direction, or a change in both velocity and direction.
Explanation:
C. Hot air balloons use convection to rise.
Answer:
x = 302 m
Explanation:
Given that,
Speed of an airplane, v = 40 m/s
Height, h = 280 m
40 m/s is the horizontal velocity we should use to solve the given problem.
Let t is the time when the hay will reach the ground. It can be calculated using second equation of motion as follows :
Here, u = 0 and a = g
Let the horizontal distance is x. It can be calculated as :
x = vt
x = 40 m/s × (7.55 s)
x = 302 m
Hence, at a distance of 302 m she have to release the hay in order to hit the cow.