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ira [324]
3 years ago
9

TEST HELP PLEASE!! WILL GIVE MEDAL TO BEST ANSWER!!

Physics
2 answers:
Veronika [31]3 years ago
7 0
C. Hot air balloons use convection to rise.
Law Incorporation [45]3 years ago
7 0
<span>hot air balloons rise due to convection. Hot air is less dense than cool air; the heated air causes the balloon to rise simply because it is lighter than an equal volume of cold air. the transfer of heat from flame to air is the convection process.</span>
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What do signal trainees do
Evgen [1.6K]

Answer:

A signal apprentice works for a rail company, learning the duties of a signal maintainer through on-the-job training and experience. As part of this apprenticeship, you work on a railway to assist a seasoned signal maintainer as they install, repair, inspect, and test signal equipment.

Explanation:

8 0
3 years ago
Which organelle is unique to plants and captures light energy for photosynthesis?
evablogger [386]
<h2>Explanation:</h2>

<h3>B. Chloroplast</h3>

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<em><u>hope</u></em><em><u> this</u></em><em><u> helps</u></em><em><u> you</u></em>

<em><u>have</u></em><em><u> a</u></em><em><u> good</u></em><em><u> </u></em><em><u>day.</u></em>

5 0
3 years ago
Read 2 more answers
A rocket takes off from Earth's surface, accelerating straight up at 47.2 m/s2. Calculate the normal force (in N) acting on an a
lions [1.4K]

Answer:

Approximately 4.61\times 10^{3}\; {\rm N} upwards (assuming that g = 9.81\; {\rm m\cdot s^{-2}}.)

Explanation:

External forces on this astronaut:

  • Weight (gravitational attraction) from the earth (downwards,) and
  • Normal force from the floor (upwards.)

Let (\text{normal force}) denote the magnitude of the normal force on this astronaut from the floor. Since the direction of the normal force is opposite to the direction of the gravitational attraction, the magnitude of the net force on this astronaut would be:

\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}.

Let m denote the mass of this astronaut. The magnitude of the gravitational attraction on this astronaut would be (\text{weight}) = m\, g.

Let a denote the acceleration of this astronaut. The magnitude of the net force on this astronaut would be (\text{net force}) = m\, a.

Rearrange \begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned} to obtain an expression for the magnitude of the normal force on this astronaut:

\begin{aligned}(\text{normal force}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= m\, (a + g) \\ &= 80.9\; {\rm kg} \times (47.2\; {\rm m\cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 4.61 \times 10^{3}\; {\rm N}\end{aligned}.

3 0
2 years ago
Explain the advantages of using parallel circuits to series circuits in wiring rooms
irina [24]

The major advantage of parallel circuit which makes it advantageous in the application of wiring rooms are the supply of equal voltage across each circuit, which is not present in series circuit.

<u> Explanation:</u>

The use of parallel circuit is preferred over series circuit while wiring the room as the parallel gives the same voltage across every circuit which keeps it safe from damaging or burning as they give consistent voltage.

Apart from this, the parallel circuit allows you for independent operation without letting use of all the equipment present in the room. Then there is scope for additional components without changing the voltage.

5 0
3 years ago
Upper A 16​-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away f
Sav [38]

Answer:

The ladder is moving at the rate of 0.65 ft/s

Explanation:

A 16​-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the building at 2 ​feet/second. We need to find the rate at which the top of the ladder moving down when the foot of the ladder is 5 feet from the​ wall.

The attached figure shows whole description such that,

x^2+y^2=256.........(1)

\dfrac{dx}{dt}=2\ ft/s

We need to find, \dfrac{dy}{dt} at x = 5 ft

Differentiating equation (1) wrt t as :

2x.\dfrac{dx}{dt}+2y.\dfrac{dy}{dt}=0

2x+y\dfrac{dy}{dt}=0

\dfrac{dy}{dt}=-\dfrac{2x}{y}

Since, y=\sqrt{256-x^2}

\dfrac{dy}{dt}=-\dfrac{2x}{\sqrt{256-x^2}}

At x = 5 ft,

\dfrac{dy}{dt}=-\dfrac{2\times 5}{\sqrt{256-5^2}}

\dfrac{dy}{dt}=0.65

So, the ladder is moving down at the rate of 0.65 ft/s. Hence, this is the required solution.

8 0
3 years ago
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