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3 years ago

TEST HELP PLEASE!! WILL GIVE MEDAL TO BEST ANSWER!!

Physics

2 answers:

Veronika [31]3 years ago

7 0

C. Hot air balloons use convection to rise.

Law Incorporation [45]3 years ago

7 0

<span>hot air balloons rise due to convection. Hot air is less dense than cool air; the heated air causes the balloon to rise simply because it is lighter than an equal volume of cold air. the transfer of heat from flame to air is the convection process.</span>

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REALLY NEED HELP WITH THIS!!!

goldenfox [79]

I don't know if this is right, but inheritance?

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3 years ago

Infrared thermometers are commonly called laser thermometers true or false?

crimeas [40]

Answer:

<h2>False </h2>

Explanation:

They are sometimes called laser thermometers as a laser is used to help aim the thermometer, or non-contact thermometers or temperature guns, to describe the device's ability to measure temperature from a distance. Infrared thermometers are a subset of devices known as "thermal radiation thermometers".

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2 years ago

The red lines on this

tino4ka555 [31]

The circular lines you see on the chart are isobars, which join areas of the same barometric pressure.

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2 years ago

Before colliding the momentum of block A is +15.0 kg*m/s, and block B is -35.0 kg*m/s. after, block A has a momentum -12.0 kg*m/

UkoKoshka [18]

The momentum of block B afterwards is $-8.0 kg m/s$ .

Explanation:

We can solve this problem by applying the principle of conservation of momentum.

In fact, the total momentum before and after the collision must be conserved. Therefore, we can write:

$p_A + p_B = p_A' + p_B'$

where:

$p_A = +15.0 kg m/s$ is the initial momentum of block A

$p_B = -35.0 kg m/s$ is the initial momentum of block B

$p_A' = -12.0 kg m/s$ is the final momentum of block A

$p_B'$ is the final momentum of block B

Solving for $p_B'$ , we find:

$p_B' = p_A + p_B - p_A' = +15.0 +(-35.0) - (-12.0)=-8.0 kg m/s$

So, the momentum of block B afterwards is $-8.0 kg m/s$ .

Learn more about momentum:

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3 years ago

An animal-rescue plane flying due east at 27 m/s drops a bale of hay from an altitude of 74 m . The acceleration due to gravity

padilas [110]

To solve this problem we will find the net speed, through the two components given. The vertical component will be found through the energy conservation theorem. Finally with speed we will find the momentum as a function of mass and speed. Given the weight we will divide it by the acceleration to find that mass.

The x component is given as

$v_x = 27m/s$