Answer:
distance between the charges is 5.12 × 10⁶ m
Explanation:
charges q₁ = -130.0 C
q₂ = 180 C
force between the charges = 8 N
force between two charge
value of K =8.975 × 10⁹ N.m²/C²
r = 5.12 × 10⁶ m
hence, distance between the charges is 5.12 × 10⁶ m.
A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)
<h3>What is power?</h3>
In physics, power (P) is the work (W) done over a period of time.
- Step 1. Calculate the work done by the bodybuilder each time.
The bodybuilder lifts a 215 kg (m) weight to a height of 0.90 m (h). Being the gravity (g) of 9.81 m/s², we can calculate the work done in each lift using the following expression.
W = m × g × h = 215 kg × 9.81 m/s² × 0.90 m = 1.9 × 10³ N
- Step 2. Calculate the work done by the bodybuilder over 10 times.
W = 10 × 1.9 × 10³ N = 1.9 × 10⁴ N
- Step 3. Calculate the power exerted by the bodybuilder.
The bodybuilder does a work of 1.9 × 10⁴ N in a 45-s span.
P = 1.9 × 10⁴ N/45 s = 421 W
A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)
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Answer: 5 m, 2 s
Explanation:
gravity is roughly 10 m/s²downward
That means in one second, the velocity will have been reduced to zero
The average speed is (10 + 0) / 2 = 5 m/s
h = vt = 5(1) = 5 m
It will take as long to fall back to the thrower from rest so total flight is 1 + 1 = 2 s
Answer: When a car is struck by lightning, the resulting electric field inside the car is zero.
Explanation: