Answer:
= 1.75 × 10⁻⁴ m/s
Explanation:
Given:
Density of copper, ρ = 8.93 g/cm³
mass, M = 63.5 g/mol
Radius of wire = 0.625 mm
Current, I = 3A
Area of the wire, 
= 
Now,
The current density, J is given as
= 2444619.925 A/mm²
now, the electron density, 
where,
=Avogadro's Number
Now,
the drift velocity,
where,
e = charge on electron = 1.6 × 10⁻¹⁹ C
thus,
= 1.75 × 10⁻⁴ m/s
Answer:
the average drift speed of the mobile electrons in the metal is 1.089 x 10⁻⁴ m/s.
Explanation:
Given;
mobility of the mobile electrons in the metal, μ = 0.0033 (m/s)/(N/C)
the electric field strength inside the cube of the metal, E = 0.033 N/C
The average drift speed of the mobile electrons in the metal is calculated as;
v = μE
v = 0.0033 (m/s)/(N/C) x 0.033 N/C
v = 1.089 x 10⁻⁴ m/s.
Therefore, the average drift speed of the mobile electrons in the metal is 1.089 x 10⁻⁴ m/s.
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