What is the image of ( 0 , -6 ) after a reflection over the line y = x?

Mathematics

1 answer:

Alla [95]3 years ago

3 0

Answer:

(-6, 0)

Step-by-step explanation:

(x, y) over y=x = (y, x)

so (0, -6) will be (-6, 0).

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Find the area of each sector.

sergey [27]

Answer:

D. $\frac{525\pi}{8}$ m²

Step-by-step explanation:

Area of the sector = ½*r²∅

Where,

Radius (r) = 15 m

Angle in radians (∅) = $\frac{7\pi}{12}$

Plug in the values into the equation

Area of sector = $\frac{1}{2} * 15^2 * \frac{7\pi}{12}$

Area of sector = $\frac{1}{2} * 225 * \frac{7\pi}{12}$

Area of sector = $\frac{1*225*7\pi}{2*12}$

Area of sector = $\frac{1,575\pi}{24}$

Simplify

Area of sector = $\frac{525\pi}{8}$

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3 years ago

Write the expression without the fraction bar.

kirill115 [55]

For problems like this you can move the y's on the bottem up top by fliping the sign of the exponent (in this case 7 to -7) and MULTIPLYING it with EVERYTHING on top, then because of properties of multplication you can add the exponents to combine them into one term (in this case add 3 and -7 to get -4) $\frac{ y^{3} }{y^{7}}=y^3 *y^{-7} = y^{3+-7}=y^{3-7}=y^-4$ If any of this does not make sense let me know and ill try to clarify better