Step-by-step explanation:
y= 5
x=3
.................
G(x) = (x+4)^4 is the answer. It's D. last choice
G(x) = (x+4)^4 shifted F(x) = x^4 4 units to the left
Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s
the only force acting on the object, is gravity, using feet will then be -32ft/s²,
was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues
so, we'll do the integral to get v(t) then

when will it reach the ground level? let's set s(t) = 0

part B) check the picture below
Each bus was filled with 54 students
Answer:
ur mom
Step-by-step explanation: