Answer: The correct answer is -
d) a dominant trait that depends on the presence of only one of many dominant alleles.
Glaucoma is an autosomal dominant trait, meaning that presence of single copy of the defective gene is enough to cause the disease.
It corresponds to a group of diseases, which cause damage in the optic nerve, leading to loss of vision and if not treated, it ultimately leads to blindness.
Thus, option D) is the right answer.
Answer:
a. PGA down, RuBP up
Explanation:
RuBP, also known as Ribulose-1,5-bisphosphate is a molecule that assist in he fixation of carbon dioxide in the Calvin Cycle or light independent reaction of photosynthesis.
RuBP is combined with carbon dioxide using the enzyme known as rubisco to form an short-lived intermediate product which divides to form two 3-carbon molecule structure known as 3-phosphoglycerate.
<em>If the concentration of carbon dioxide is suddenly reduced, it thus means that the rate of production of 3-phosphoglycerate will reduce as carbon dioxide becomes a limiting factor. Hence, 3-phosphoglycerate's concentration will reduce while more RuBP will become available as a result.</em>
The correct option is a.
A. to find out if a hypothesis is correct.
Answer:
0, 2, 4
Explanation:
The process of cellular respiration takes place in for phases which oxidizes the glucose molecule to the provide energy molecule called ATP.
Along with ATP, the process releases the metabolic water and carbon dioxide gas. In the oxidation of one glucose molecules, about 6 molecules of CO₂ are released. These CO₂ molecules are produced in the following manner:
1. Glycolysis: CO₂ gas is not produced during this reaction but only ATP and NADH are produced.
2. Pyruvate decarboxylation: the process converts the pyruvate produced by glycolysis to Acetyl-CoA. Formation of 1 Acetyl-CoA produces 1 CO₂ and since 2 Acetyl-CoA is produced therefore produces 2 CO₂ molecules.
3. Citric acid cycle: The cycle converts 2 Acetyl-CoA and produces 4 CO₂ in two cycles converting each Acetyl-CoA.
Thus, 0, 2, 4 is correct.
<span>The answer is A -The red geranium is heterozygous for red flowers (Rr).
We know that the red flower, to be red needs to have at least a dominant allele, so it could be either Rr or RR.
Let's try both scenarios.
If the white</span><span> geranium (rr) is being crossed with RR, all the offspring would be red with genotype: Rr.
On the other hand, if the flower is Rr and it's being crossed with rr, that would result in </span><span>half of the new generation plants having red flowers and the other half white flowers.</span>
