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xxTIMURxx [149]
2 years ago
11

What is the equation of the perpendicular bisector of line AB?

Mathematics
2 answers:
Usimov [2.4K]2 years ago
7 0
It should be B

Because the slope of AB is 6/5 and when you are finding it’s perpendicular bisector then the slope of that line should be the negative reciprocal, it should be -5/6.
VikaD [51]2 years ago
6 0
The answer you get should be b
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The vertices of a triangle are located at X(-2,-1), Y(2,5) and Z(4,3). What is the perimeter of this triangle?
Lana71 [14]
If you plot the points you will find you have to use the distance formula. Pick out 2 pairs label them (x1,y1) (x2,y2) then plug it into the distance formula. The repeat for the other sides. So you should get (2,5) (4,3) plug into distance formula what is get it distance between those two points, then (4,3) (-2,-1) plug into distance formula to get an answer, lastly (-2,-1) (2,5) plug in. Now you have three answers add all together and here is your perimeter of a triangle.
3 0
2 years ago
John and his friend ordered lunch at a local sandwich shop. They each ordered a soft drink that costs $1.65. John orders a whole
ExtremeBDS [4]

Answer:

a. $12.54 = $ 1.65 + c/2 + c b. $ 7.26

Step-by-step explanation:

a. What equation can you use to find the cost c of a sandwich

Let c be the cost of a whole ham sandwich. Now, the total bill = cost of drinks + cost of half a ham sandwich  + cost of a whole ham sandwich.

total bill = $ 12.54, cost of drinks = $ 1.65, cost of half a ham sandwich = c/2 and cost of a whole ham sandwich = c. So,

$12.54 = $ 1.65 + c/2 + c

b. What is the value of c

We then solve for c in the equation $12.54 = $ 1.65 + c/2 + c

collecting like terms, we have

$12.54 - $ 1.65 = c/2 + c

$ 10.89 = 3c/2

multiplying through by 2, we have

$ 10.89 × 2 = 3c

$ 21.78 = 3c

dividing through by 3, we have

c = $ 21.78/3

= $ 7.26

4 0
2 years ago
Help
Natali5045456 [20]

Answer:

1.9 \sqrt{3}

Step-by-step explanation:

3.8 is 2x 3.8/2 is 1.9

5 0
2 years ago
Given sinθ=- 3/5 and cscθ=-5/3 in quadrant III, find the value of other trigonometric functions using a Pythagorean Identity. Sh
Yakvenalex [24]
Let ABC be a triangle in the 3rd quadrant, right-angled at B. 
 So, AB-> Perpendicular BC -> Base AC -> Hypotenuse. 
Given: sinθ=-3/5 cosecθ=-5/3 
 According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
 Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
 Since sinθ=Perpendicular/Hypotenuse ,
 AC=5 and AB=3
 Substituting these values in equation (1)
 
〖BC〗^2=〖AC〗^2-〖AB〗^2

 ă€–BC〗^2=5^2-3^2
 

 ă€–BC〗^2=25-9

 ă€–BC〗^2=16

 BC=4 units

 Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
 So,cosθ=Base/Hypotenuse Cosθ=-4/5 
 secθ=Hypotnuse/Base secθ=-5/4 
 tanθ=Perpendicular/Base tanθ=3/4  
 cotθ=Base/Perpendicular cotθ=4/3
4 0
2 years ago
The equation of the circle with center (3, -2) and radius 7 is<br> (X blank) + (y blank)
deff fn [24]

Answer:

Step-by-step explanation:

(x-3)^2 + (y+2)^2 = 7^2

5 0
3 years ago
Read 2 more answers
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