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Tanzania [10]
3 years ago
7

A transverse wave on a string has an amplitude A. A tiny spot on the string is colored red. As one cycle of the wave passes by,

what is the total distance traveled by the red spot?a.) 4Ab.) 1/2 Ac.) 1/4 Ad.) Ae.) 2A
Physics
1 answer:
DiKsa [7]3 years ago
6 0

Since it's a transverse wave, a particle on the string moves left and right as the wave passes by, but the particle doesn't travel forward or backward at all.

So the little red dot moves 'A' to the left, then 'A' back to the center, then 'A' to the right, then 'A' back to the center again.

All together, the red dot moves a total distance of <em>4A . (choice 'a')</em>

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Vlad1618 [11]

A: makes work easier to do.

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3 years ago
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On a cold winters da,y,If you left a drink setting outside,it could freeze.Explain why in a complete sentence
sertanlavr [38]
Hello!

On a cold winters day, if you left a drink setting outside, it could freeze because the heat (related to the kinetic energy) of the atoms in the drink will be transferred to the environment to achieve energy equilibrium. 

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4 years ago
IF you are in Space and push a bowling what happens to you and the bowling ball?
Anastaziya [24]

Answer:

The bowling ball did not change size or shape- the only thing that changed was the amount of gravity that pulls on it. But the mass of the bowling ball would never change. A bowling ball with a mass of 12 pounds on earth will have the mass of 12 pounds on the moon! Mass is the amount of atoms that a space fills.

Explanation:

I hope this helps! :D

4 0
3 years ago
An athlete can twirl a baton so that it reaches an angular velocity of 12 rad/s from rest in 0.5 s. If the length of a uniform b
NikAS [45]

Answer:

The torque needed is 46.08 Nm

Explanation:

Given;

angular velocity, ω = 12 rad/s

time of motion, t = 0.5 s

length of the baton, r = 0.8 m

mass of the baton, 0.5 kg

The torque needed to  reach the angular velocity is given by;

τ = F x r

where;

F is the centripetal force of the baton

r is the length of the baton = radius of the circular motion of the baton

F_c =ma_c= \frac{mv^2}{r} = m\omega^2 r

Torque is given by;

\tau = F_c *r\\\\\tau = m \omega^2 r *r\\\\\tau = m \omega^2 r^2 \\\\\tau = (0.5)(12)^2(0.8)^2\\\\\tau = 46.08 \ N m

Therefore, the torque needed is 46.08 Nm

6 0
3 years ago
I need the answer asap plz!!
Vesnalui [34]

Answer:

266.7k

Explanation:

Given parameters:

Initial pressure  = 36Pa

Initial temperature  = 300k

New pressure  = 32Pa

Unknown:

New temperature  = ?

Solution:

To solve this problem, we have to apply the combined gas law when the volume is constant;

in this instant, when the volume is constant, the pressure of a given mass of gas varies directly with the absolute temperature.

          \frac{P_{1} }{T_{1} }   = \frac{P_{2} }{T_{2} }  

P and T are pressure and temperature

1 and 2 are initial and final states

  Insert the parameters and solve;

       \frac{36}{300}   = \frac{32}{T_{2} }  

      T₂  = 266.7k

7 0
3 years ago
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