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irinina [24]
3 years ago
13

Which statement is true about the energy of electromagnetic radiation? A.the frequency of the emmited radiation is inversely pro

portional to its energy. B.the frequency of the emitted radiation is directly proportional to its energy C.the wavelength of the emitted radiation is directly proportional to its energy. D.the amplitude of the emitted radiation is inversely proportional to its energy.
Physics
2 answers:
Alexandra [31]3 years ago
7 0

Answer: Option (B) is the correct answer.

Explanation:

The radiation in which waves of electromagnetic field travel or propagate through the space and carries electromagnetic radient energy is known as electromagnetic radiation.

The relation between energy and frequency is as follows.

                    E = h \nu  ............ (1)

where,      E = energy

                h = plank's constant

           \nu = frequency

Therefore, the frequency of the emitted radiation is directly proportional to its energy.

Also, frequency is proportional to c over wavelength. The relation is as follows.

                \nu = \frac{c}{\lambda} ........ (2)

where,      \nu = frequency

                         c = speed of light

                     \lambda = wavelength

Placing the value of frequency from equation (2) to equation (1) as follows.  

                          E = \frac{hc}{\lambda}

Thus, the wavelength of the emitted radiation is inversely proportional to its energy.

frozen [14]3 years ago
5 0
<span>The frequency of the emitted radiation is directly proportional to its energy </span>
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n isolated charged soap bubble of radius R0=7.45 cmR0=7.45 cm is at a potential of V0=307.0 volts.V0=307.0 volts. If the bubble
Gnesinka [82]

Complete Question

An isolated charged soap bubble of radius R0 = 7.45 cm  is at a potential of V0=307.0 volts. V0=307.0 volts. If the bubble shrinks to a radius that is 19.0%19.0% of the initial radius, by how much does its electrostatic potential energy ????U change? Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble r

Answer:

The difference is    U_f -U_i = 16 *10^{-7} J

Explanation:

From the question we are told that

     The radius of the soap bubble  is  R_o =  7.45 \ cm =  \frac{7.45}{100} =  0.0745 \ m

      The potential of the soap bubble is  V_1  =307.0 V

      The new radius of the soap bubble  is R_1 =  0.19 * 7.45=1.4155\ cm = 0.014155 \ m

The initial electric potential is mathematically represented as

     U_i  = \frac{V_1^2 R_o }{2k }

The final  electric potential is mathematically represented as

    U_f  = \frac{V_2^2 R_1 }{2k }

The initial potential is mathematically represented as

     V_1 =  \frac{kQ}{R_o}

The final  potential is mathematically represented as

        V_2 =  \frac{kQ}{R_1}

Now  

         \frac{V_2}{V_1}  =  \frac{R_o}{R_1}

substituting values

        \frac{V_2}{V_1}  =  \frac{7.45}{1.4155} =   \frac{1}{0.19}

=>      V_2 =  \frac{V_1}{0.19}

    So

         U_f  = \frac{V_1^2 R_2 }{2k * 0.19^2}

Therefore

        U_f -U_i = \frac{V_1^2 R_2 }{2k * 0.19^2} - \frac{V_1^2 R_o }{2k }

       U_f -U_i =     \frac{V_1^2}{2k} [\frac{ R_1 }{ * 0.19^2} - R_o]

where k is the coulomb's constant with value 9*10^{9} \  kg\cdot m^3\cdot s^{-4}\cdot A^2.

substituting values

       U_f -U_i =     \frac{307^2}{9 * 10^{9}} [\frac{ 0.014155 }{ 0.19^2} - 0.0745]

       U_f -U_i = 16 *10^{-7} J

           

     

8 0
3 years ago
The rate constant of a reaction is 7.8 × 10−3 s−1 at 25°C, and the activation energy is 33.6 kJ/mol. What is k at 75°C? Enter yo
Alexus [3.1K]

Answer:

k_2 = 7.815 * 10^-3 s^-1

Explanation:

Given:

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- rate constant of reaction k_2 = ?    @  T_2 = 75 C

- The activation energy E_a = 33.6 KJ/mol

- Gas constant R = 8.314472 KJ / mol . K

Find:

- rate of reaction k_2 @ T_2 = 75 C

Solution:

- we will use a combined form of Arrhenius equations that relates rate constants k as function of E_a and temperatures as follows:

                              k_2 = k_1 * e ^ [(E_a / R) * ( 1 / T_1 - 1 / T_2 )

- Evaluate             k_2 = 7.8 * 10^-3* e^[(33.6 / 8.314472)*(1/298 -1/348)

- Hence,                k_2 = 7.815 * 10^-3 s^-1

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What is the kinetic energy of a 145 g baseball moving at 42 m/s?
klio [65]
Answer:
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Explanation:
Kinetic energy is calculated using the following rule:
KE = (1/2)*v* v^2
Where:
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Substitute in the above equation to get the kinetic energy as follows:
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Answer:

a) The force is zero, or the displacement is zero, or the angle is 180 degrees

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Answer:

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Explanation:

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V=(4/3)πr³ ⇒

\frac{dV}{dt}=\frac{4}{3}\pi3r^{2}\frac{dr}{dt}\\\frac{dV}{dt}=4\pi r^{2}(-0.1\frac{cm}{min})

and r=14cm then

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4 0
4 years ago
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