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4 years ago

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2 answers:

4 0

I think the correct answer from the choices listed above is the third option. The function of the slip rings in an electric generator would be producing a path for current to flow. Hope this answers the question. Have a nice day. Feel free to ask more questions.

Mama L [17]4 years ago

3 0

<h3><u>Answer;</u></h3>

producing a path for current to flow

<h3><u>Explanation;</u></h3>

An AC generator is a device that converts mechanical energy into electrical energy using the principle of electromagnetic induction.
<em><u>Slip rings are two hollow rings to which two ends of the armature coil are connected. These rings rotate with the rotation of the coil. They function to to allow for electrical contact with the brushes.</u></em>
Slip rings therefore, provide a means for connecting the rotating armature to an external circuit.

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2 years ago

NEED A PHYSICS EXPERT TO HELP ME PLS

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Answer:

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3 years ago

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4 years ago

The hydraulic oil in a car lift has a density of 8.53 x 102 kg/m3. The weight of the input piston is negligible. The radii of th

navik [9.2K]

Answer:

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(b) the input force is 37.49 N

Explanation:

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radius of plunger, r₁ = 0.135 m

radius of piston, r₂ = 5.43 x 10⁻³ m

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$P =\frac{F}{A}$

Where;

P is pressure

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A is circular area = πr²

$\frac{F_1}{A_1} =\frac{F_2}{A_2} \\\\F_2 = \frac{F_1*A_2}{A_1} =\frac{F_1* \pi r_2^2}{\pi r_1^2} = \frac{F_1* r_2^2}{ r_1^2} \\\\F_2 = \frac{22600*(5.43*10^{-3})^2 }{(0.135)^2}\\\\F_2 = 36.56 \ N$

Part (b) The input force needed to support 22600-N weight, when the bottom surface of the output plunger is 1.20 m above that of the input plunger

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But, F = PA and A = πr²

$F_2 = F_1(\frac{A_2}{A_1} ) + \rho gh*A_2\\\\F_2 = F_1(\frac{r_2^2}{r_1^2} )+\rho gh(\pi r_2^2)\\\\F_2 = 22600(\frac{5.43*10^{-3}}{0.135})^2 \ + 853*9.8*1.2*\pi (5.43*10^{-3})^2\\\\F_2=36.56 + 0.93\\\\F_2 = 37.49 \ N$

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3 years ago

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