speed of the car is given on the road

reaction time is given as

now we can find the distance that it will move during this reaction time

now the deceleration of the car is 10 m/s^2
so the distance that it will move before stop is given by



so the total distance that it require to stop is given as

while the deer is standing at distance 38 m
so the car will stop 2.8 m before the position of deer
Answer:
The height is "89.61 m". A further explanation is given below.
Explanation:
According to the question,
Mass of rocket,
m = 5 kg
Time,
t = 4.6 s
Initial speed of rod
u = o m/s
Final speed,
v = 39 m/s
drag,
= 60 N
So,
⇒ acceleration, 


⇒ 



Now,
The thrust will be:
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
The height will be:
⇒ 



Answer:
437 J
Explanation:
Parameters given:
Weight of child, W = 230 N
Height of swing, h = 1.9 m
Gravitational Potential Energy is given as:
P. E. = m*g*h = W*h
m = mass
h = height above the ground
W = weight
P. E. = 230 * 1.9
P. E. = 437 J
Answer:
The discharge rate is 
Explanation:
From the question we are told that
The diameter is 
The head is 
The coefficient of contraction is 
The coefficient of velocity is 
The radius is mathematically evaluated as

substituting values


The area is mathematically represented as

substituting values


The discharge rate is mathematically represented as

substituting values

