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kati45 [8]
4 years ago
8

Help

Physics
2 answers:
marishachu [46]4 years ago
4 0
I think the correct answer from the choices listed above is the third option. The function of the slip rings in an electric generator would be producing a path for current to flow. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Mama L [17]4 years ago
3 0
<h3><u>Answer;</u></h3>

producing a path for current to flow

<h3><u>Explanation;</u></h3>
  • An AC generator is a device that converts mechanical energy into electrical energy using the principle of electromagnetic induction.
  • <em><u>Slip rings are two hollow rings to which two ends of the armature coil are connected. These rings rotate with the rotation of the coil. They function to  to allow for electrical contact with the brushes.</u></em>
  • Slip rings therefore, provide a means for connecting the rotating armature to an external circuit.
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What is the energy of a photon emitted with a wavelength of 518 nm?
navik [9.2K]

Answer:

C

Explanation:

4 0
3 years ago
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You're driving down the highway late one night at 22 m/s when a deer steps onto the road 38 m in front of you. Your reaction tim
sleet_krkn [62]

speed of the car is given on the road

v = 22 m/s

reaction time is given as

t = 0.50 s

now we can find the distance that it will move during this reaction time

d_1 = 22* 0.50 = 11 m

now the deceleration of the car is 10 m/s^2

so the distance that it will move before stop is given by

v_f^2 - v_i^2 = 2 a d

0^2 - 22^2 = 2*(-10)*d

d = 24.2 m

so the total distance that it require to stop is given as

d = 24.2 + 11 = 35.2 m

while the deer is standing at distance 38 m

so the car will stop 2.8 m before the position of deer


3 0
3 years ago
During take-off a 5kg model rocket, initially at rest, burns fuel for 4.6s causing its speed to increase from rest to 39m/s duri
MrRa [10]

Answer:

The height is "89.61 m". A further explanation is given below.

Explanation:

According to the question,

Mass of rocket,

m = 5 kg

Time,

t = 4.6 s

Initial speed of rod

u = o m/s

Final speed,

v = 39 m/s

drag,

= 60 N

So,

⇒ acceleration, a=\frac{v-u}{t}

                              =\frac{39-0}{4.6}

                              = 8.478 \ m/s^2

⇒ F_{net}= Net \ force

           =ma

           =5\times 8.478

           =42.89 \ N

Now,

The thrust will be:

⇒ Thrust-weight-drag=Net \ force

⇒ Thrust-(5\times 9.8)-60=42.89

⇒           Thrust-49-60=42.89

⇒                 Thrust-109=42.89

⇒                           Thrust=42.89+109

⇒                           Thrust=151.89 \ N

The height will be:

⇒ h=\frac{1}{2} at^2

      =\frac{1}{2}\times 8.47\times (4.6)^2

      =\frac{1}{2}\times 8.47\times 21.16

      =89.61 \ m

5 0
3 years ago
A child with a weight of 230 N swings on a playground swing attached to 1.90 m long chains. What is the gravitational potential
nlexa [21]

Answer:

437 J

Explanation:

Parameters given:

Weight of child, W = 230 N

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Gravitational Potential Energy is given as:

P. E. = m*g*h = W*h

m = mass

h = height above the ground

W = weight

P. E. = 230 * 1.9

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7 0
3 years ago
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A sharp edged orifice with a 60 mm diameter opening in the vertical side of a large tank discharges under a head of 6 m. If the
Ierofanga [76]

Answer:

The discharge rate is Q = 0.0192 \  m^3 /s

Explanation:

From the question we are told that

   The  diameter is  d =  60 \ mm   =  0.06 \ m

    The  head is  h  =  6 \ m

     The  coefficient of contraction is  Cc  =  0.68

     The  coefficient of  velocity is  Cv  =  0.92

The radius is mathematically evaluated as

         r =  \frac{d}{2}

substituting values

        r =  \frac{ 0.06 }{2}

        r =  0.03 \ m

The  area is mathematically represented as

      A =  \pi r^2

substituting values

      A =  3.142 *  (0.03)^2

      A = 0.00283 \ m^2

 The  discharge rate is mathematically represented as

        Q =  Cv *Cc  *  A  *  \sqrt{ 2 * g *  h}

substituting values

       Q = 0.68 *  0.92*   0.00283  *  \sqrt{ 2 * 9.8 *  6}

       Q = 0.0192 \  m^3 /s

6 0
3 years ago
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