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4 years ago

On a cold winters da,y,If you left a drink setting outside,it could freeze.Explain why in a complete sentence

1 answer:

6 0

Hello!

On a cold winters day, if you left a drink setting outside, it could freeze because the heat (related to the kinetic energy) of the atoms in the drink will be transferred to the environment to achieve energy equilibrium.

Heat transfer occurs by various mechanisms, flowing from the hottest body to the coldest, that's why the heat goes from the drink, which has a higher temperature (and kinetic energy) to the environment, which has a lower temperature. This is described by the second law of thermodynamics

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1. After being struck by a bowling ball, a 1.5 kg bowling pin moving to the right at +3.0 m/s collides with

salantis [7]

Answer:

a) Final velocity of second bowling pin is 2.5m/s.

b) Final velocity of second bowling pin is 3 m/s.

Explanation:

Let 'm' be the mass of both the bowling pin -

m = 1.5 kg

Initial velocity of first bowling pin -

$v_{1} = 3 m/s$

In any type of collision between two bodies in horizontal plane , momentum is conserved along the line of impact.

a) Since , initial velocity of second bowling pin is 0 m/s -

Initial momentum ,

$p_{1} = mv_{1}$

Final velocity of first bowling pin , $v_{2} = 0.5m/s$ [Considering initial direction of motion of the first bowling pin to be positive]

Let $u_{2}$ be the final velocity of the second bowling pin.

∴ Final momentum ,

$p_{2} = mv_{2} + mu_{2}$ .

Now ,

$p_{1} = p_{2}$

∴ $mv_{1} = mv_{2} + mu_{2}$

∴ $u_{2}$ = 3 - 0.5 = 2.5 m/s

∴ Final velocity of second bowling pin is 2.5 m/s.

b) Since , initial velocity of second bowling pin is 0 m/s -

Initial momentum ,

$p_{1} = mv_{1}$

Final velocity of first bowling pin , $v_{2} = 0m/s$ [given][Considering initial direction of motion of the first bowling pin to be positive]

Let $u_{2}$ be the final velocity of the second bowling pin.

∴ Final momentum ,

$p_{2} = mv_{2} + mu_{2}$ .

Now ,

$p_{1} = p_{2}$

∴ $mv_{1} = mv_{2} + mu_{2}$

∴ $u_{2}$ = 3 - 0 = 3 m/s

∴ Final velocity of second bowling pin is 3 m/s.

7 0

3 years ago

Slushy snow in standing water can increase hydroplaning risk.

Nesterboy [21]

Answer:

yes

Explanation:

Slushy snow can increase hydroplaning risk

my source: https://quizlet.com/29357993/chapter-12-practice-test-flash-cards/

6 0

3 years ago

You have two steel solid spheres. sphere 2 has twice the radius of sphere 1. part a by what factor does the moment of inertia i2

sertanlavr [38]

Answer:

moment of inertia of sphere 2 is 32 times the moment of inertia of sphere 1

Explanation:

The moment of inertia of a solid sphere about its axis is

$I=\frac{2}{5}MR^2$

where

M is the mass of the sphere

R is the radius of the sphere

The mass of the sphere can be rewritten as

$M=\rho V$

where

$\rho$ is the density

$V=\frac{4}{3}\pi R^3$ is the volume of the sphere

So the moment of inertia becomes

$I=\frac{2}{5}(\frac{4}{3}\pi \rho R^3)R^2 = \frac{8}{15}\pi \rho R^5$

Calling R the radius of sphere 1, the moment of inertia of sphere 1 is

$I_1=\frac{8}{15}\pi \rho R^5$

where $\rho$ is the density of steel, since the sphere is made of steel

Sphere 2 has twice the radius of sphere 1, so

R' = 2R

and so its moment of inertia is

$I_2=\frac{8}{15}\pi \rho R'^5=\frac{8}{15}\pi \rho (2R)^5=32(\frac{8}{15}\pi \rho R^5)=32I_1$

So, the moment of inertia of sphere 2 is 4 times the moment of inertia of sphere 1.

4 0

3 years ago

15cm3 block of gold weighs 2.8N it is carefully submerged in a tank of mercury. one cm3 of mercury weight 0.!3n a will the mer

NNADVOKAT [17]

You have said that 15cm³ of gold weighs 2.8N. So I may infer that each cm³
of gold weighs about 0.19N. When I compare that figure with the 0.13N per cm³
of mercury, it becomes immediately apparent that the gold is more dense than
mercury. Therefore, the sample of gold, no matter what its size or weight, will
displace its total volume of mercury, and will go on to sink entirely beneath the
waves in the mercury.

3 0

3 years ago

Plzzz answer this correctly

viva [34]

Answer:

D, the acceleration of A is twice that of b.

Explanation: in four seconds b got to ten, in two seconds a got to 20. Going 10m/s faster in half the time is going twice the acceleration

7 0

3 years ago