We need to convert the mileage from mi/gal units into to km/L units using the conversion factors.
(31.0 mi/gal) x (1 km / 0.6214 mi) x (1 gal / 3.78 L) = 13.20 km/L
Next, we divide the distance by the mileage.
(142 km) / (13.20 km/L) = 10.79 L
<span>Therefore, you need 10.79 liters of gasoline.</span>
Answer:

Step-by-step explanation:
we know that
The circumference of a circle is equal to

In this problem we have

substitute

Remember that
subtends the arc length of the complete circle
so
by proportion
Find the measure of the central angle for an arc length of 

Answer:
(1, -2)
Step-by-step explanation:
midpoint x = (x₁ + x₂) / 2
midpoint y = (y₁ + y₂) / 2

= (1, -2)
Answer:
The surface area of the award is 
Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
![SA=6^{2}+4[\frac{1}{2}(6)(8)]=132\ in^{2}](https://tex.z-dn.net/?f=SA%3D6%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%286%29%288%29%5D%3D132%5C%20in%5E%7B2%7D)