Which of the following are not polynomials

Mathematics

1 answer:

yKpoI14uk [10]4 years ago

6 0

Answer:

A, B, C

Step-by-step explanation:

The variables in a polynomial term are non-negative integers.

A: x is to 1/2 power (square root) . . . not a polynomial

B: x is to -2 power . . . not a polynomial

C: x is to -2 power . . . not a polynomial

D: x is to powers of 2 and 1 . . . is a polynomial

You might be interested in

Find slope through (3,16) and (8,18)

MissTica

2/5 is the answer hope this helped

6 0

3 years ago

Find an identity for cos(4t) in terms of cos(t)

mestny [16]

So you can do this multiple ways, I'll do this the way that I think makes sense the l most easily.

Cos (0) = 1
Cos (pi/2)=0
Cos (pi) =-1
Cos (3pi/2)=0
Cos (2pi)=1

Now if you multiply the inside by 4, the graph oscillates more violently (goes up and down more in a shorter period).
But you can always reduce it.
Cos (0)= 1
Cos (4pi/2) = cos (2pi)=1
Cos (4pi) =Cos (2pi) =1 (Any multiple of 2pi ==1)
etc...
the pattern is that every half pi increase is now a full period as apposed to just a quarter of one. That's in theory.

Now that you know that, the identities of Cosine are another beast, but mathematically.
You have.

Cos (2×2t) = Cos^2 (2t)-Sin^2 (2t)
Sin^2 (t)=-Cos^2 (t)+1..... (all A^2+B^2=C^2)
Cos (2×2t) = Cos^2 (t)-(-Cos^2 (t)+1)
Cos (2×2t)= 2Cos^2 (2t) - 1

2Cos^2 (2t) -1= 2 (Cos^2(t)-Sin^2(t))^2 -1
(same thing as above but done twice because it's cos ^2 now)
convert sin^2
2Cos^2 (2t)-1 =2 (Cos^2 (t)+Cos^2 (t)-1)^2 -1
2 (2Cos^2(t)-1)^2 -1
2 (2Cos^2 (t)-1)(2Cos^2 (t)-1)-1
2 (4Cos^4 (t) - 2 (2Cos^2 (t))+1)-1
Distribute

8Cos^4 (t) -8Cos^2 (t) +1

Cos (4t) =8Cos^4-8Cos^2 (t)+-1

5 0

3 years ago

Which equation describes the graphed function?

Oxana [17]

Using translations, it is found that the equation the represents the graphed function is:

$y = -f(x) - 3$ , given by option C.

----------------------------------

The parent function is $f(x) = \sqrt{x}$ .
<u>As x increases, it's value increases. In the graph, as x increases, it decreases</u>, thus it was multiplied by -1, that is, $-f(x)$ .
The parent function is defined for $x \geq 0$ , and the same is valid for the function in the graph, thus we have $f(x)$ and not $f(-x)$ .
The initial value of the parent function is $y = 0$ , here it is $y = -3$ , thus it was shifted down 3 units, that is, $y = -f(x) - 3$ , and the correct option is C.