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Zolol [24]
3 years ago
8

Given 2x+y=6 perform the necessary operations to put equation into the proper general form.Explain in complete sentences how you

knew that the equation was a proper general form
Mathematics
2 answers:
FrozenT [24]3 years ago
8 0

Answer:

2x + y -6 = 0

Step-by-step explanation:

The general form is Ax+By + C= 0. It requires that A and B be greater than 1 (not fractions or decimals) and A is positive. This equation is 2x + y = 6 is almost already in the form.  Subtract C to both sides to make it general form. 2x + y - 6 =0. The coefficients of the x and y are greater than 1 and 2 is positive. This meets the requirements.

dlinn [17]3 years ago
8 0

Answer: 2x + y -6 = 0

Step-by-step explanation:

The general form is .  A and B must be greater than 1  and A is positive  Subtract C to both sides to make it general form. 2x + y - 6 = 0

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I don't know what to do
RUDIKE [14]
Just do what is says to do i can answer it for u but im not sure if it will be correct
i have did this problem before tho

6 0
3 years ago
SOLVE BY GRAPHING
natka813 [3]

Answer:

x=2 and y=3.

Step-by-step explanation:

Let the one number be x and the other number be y.

ATQ, 2x=1+y and x+y=5. x=2 and y=3.

8 0
3 years ago
If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes
anyanavicka [17]

ANSWER

x  =  2 \: \: or \:  \:  x  =  15

Or

x  =   - 2 \: \: or \:  \:  x  =   -  15

EXPLANATION

The given polynomial is

f(x) = {x}^{2}  + kx + 30

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

m + n =  -  \frac{b}{a}  =  -k

and the product of roots is

mn =  \frac{c}{a}  = 30

The square difference of the zeroes is given by the expression.

( {m - n})^{2} =  {(m + n)}^{2} - 4mn

From the question, this difference is 169.

This implies that:

( { - k)}^{2}  - 4(30) = 169

{  k}^{2}  -120= 169

k^{2} = 289

k=  \pm \sqrt{289}

k=  \pm17

We substitute the values of k into the equation and solve for x.

f(x) = {x}^{2}   \pm17x + 30

f(x) = (x  \pm2)(x  \pm 15)

The zeroes are given by;

(x  \pm2)(x  \pm 15) = 0

x  =  \pm2 \: \: or \:  \:  x  =  \pm 15

5 0
3 years ago
Find the sum.<br> 2(-5y+6)+(2y-8)
kotegsom [21]

Answer: I am just hoping that this is the correct answer

Step-by-step explanation:

2(-6 + -5y) + (2y + -8) = 0

(-6 * 2 + -5y * 2) + (2y + -8) = 0

(-12 + -10y) + (2y + -8) = 0

Reorder the terms:

-12 + -10y + (-8 + 2y) = 0

Remove parenthesis around (-8 + 2y)

-12 + -10y + -8 + 2y = 0

Reorder the terms:

-12 + -8 + -10y + 2y = 0

Combine like terms: -12 + -8 = -20

-20 + -10y + 2y = 0

Combine like terms: -10y + 2y = -8y

-20 + -8y = 0

Solving

-20 + -8y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '20' to each side of the equation.

-20 + 20 + -8y = 0 + 20

Combine like terms: -20 + 20 = 0

0 + -8y = 0 + 20

-8y = 0 + 20

Combine like terms: 0 + 20 = 20

-8y = 20

Divide each side by '-8'.

y = -2.5

Simplifying

y = -2.5

4 0
3 years ago
It takes 10 workers 5 days to finish a road repair when working 2 hours a day! How many days would it take 2 people working it a
Tanzania [10]

Answer:

the answer is 10 days

Step-by-step explanation:

10 workers⋅5 days ⋅2 hoursday=100 worker-hours

2 workers ⋅5 hoursday=10 workers-hoursday

100 worker-hours⋅1 day10 worker-hours=10 days

3 0
2 years ago
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