
Expanding the left side gives

which gives two solutions,

and

. But if

, then

, but this number isn't real, so

is an extraneous solution. Meanwhile if

, you get

, so this solution is correct.
"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.
Answer:
4 textbooks
Step-by-step explanation:
3 kg = 3000 g
3000 ÷ 650 = 4.61......
Maximum number is 4 as 0.61... book being carried is not possible
Hope this helped and brainliest please
Answer:
704
Step-by-step explanation:
calculator
Well.. There's 3y-2=y+4 right?
Add 2 and you get 3y=y+6
Minus y- you get 2y=6
Divide it at 2 and you get y=3.
Sorry for the explanation but I'm from another country and this is the best I can