4 - 4y - y² = 0
-y² - 4y + 4 = 0
y = -(-4) ± √((-4)² - 4(4)(-1))
2(-1)
y = 4 ± √(16 + 16)
-2
y = 4 ± √(32)
-2
y = 4 ± 4√(2)
-2
y = 4 + 4√(2) or y = 4 - 4√(2)
-2 -2
y = -2 - 2√(2) or y = -2 + 2√(2)
The answer is C.
Answer:
c and d
Step-by-step explanation:
alternate interior angles are angles on different sides, but they at interior (inside)
Answer: f(x) = (x + 3)(x – 7)
Step-by-step explanation: Use "standard form" of the function and insert values given: vertex (2,-25) intercept point (7,0)
f(x) = a(x-h)² + k from vertex, h is 2 y is -25 from intercept, x is 7 f(x) is 0
to find a, 0 = a(7-2)² +(-25) 0 = a(7-2)² -25 add 25 to both sides
25 = a(5)² 25 = 25a 25/25 = a 1=a (seems useless but verifies implied "a"coefficient is 1)
f(x) = a(x-h)² + k solve to get the quadratic form
f(x) = (x-2)² -25 (x - 2)² is x² -4x +4
f(x) = x² -4x +4 -25 simplify
f(x) = x² -4x - 21 then factor
f(x) = (x + 3)(x - 7)
Ummm I think you should email your teacher because they can always help!!
Y=3x-2 because (0,-2) is the y intercept (b) and m is the slope.
