What is this -5=1-6x+6

Which equation represents a proportional relationship between the x and y values?

noname [10]

D So yea or A I think at least try D

6 0

3 years ago

Read 2 more answers

What is 40.99 times 2.1

posledela

Answer:

86.079

Step-by-step explanation:

40.99*2.1

7 0

3 years ago

Read 2 more answers

) f) 1 + cot²a = cosec²a

notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

$\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}$

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

$\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}$

Another identity is:

$\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}$

Therefore:

$\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}$

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

$\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}$

Another identity:

$\displaystyle \large{\sin^2x+\cos^2x=1}$

Therefore:

$\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}$

Hence proved, this is proof by using identity helping to find the specific identity.

6 0

3 years ago

The area of triangle B is 25 times greater than the area of triangle A.The perimeter of triangle B is how many times greater tha

Tpy6a [65]

<span>The ratio of areas is the square of the ratio of perimeters;
The area of triangle B / The area of triangle A = 25 ;
The perimeter of triangle B / The perimeter of triangle A = </span> $\sqrt{25} = 5 ;$
The perimeter of triangle B is 5many times greater than the perimeter of<span>triangle A!</span>

7 0

3 years ago

Read 2 more answers

The Bessel function or order zero of the first kind may be defined by. Find the radius of convergence of J0(x).

fenix001 [56]

Answer:

Step-by-step explanation:

The Bessel function or order zero of the first kind may be defined by the solution - to Bessel's differential equation - which is a finite value at the origin X=0 for positive or negative whole numbers (integers) or positive alpha (α) values.

6 0

3 years ago