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Vikki [24]
3 years ago
8

The area of triangle B is 25 times greater than the area of triangle A.The perimeter of triangle B is how many times greater tha

n the perimeter of triangle A?
Mathematics
2 answers:
Tpy6a [65]3 years ago
7 0
<span>The ratio of areas is the square of the ratio of perimeters;
The area of triangle B / The area of triangle A = 25 ;
The perimeter of triangle B / The perimeter of triangle A = </span>\sqrt{25} = 5 ;
The perimeter of triangle B is 5many times greater than the perimeter of<span>triangle A!</span>
SVETLANKA909090 [29]3 years ago
3 0
The perimeter of triangle B is 5 times greater than that of A.
The ratio of areas in this example is 1:25.
The ratio of areas is the square of the ratio of perimeters.
\sqrt1 :  \sqrt{25} =1 : 5
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Cos(theta)= -.9041, 180degress&lt; theta &lt;270degress
AVprozaik [17]

Answer:

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Step-by-step explanation:

We know

cos\theta=-.9041

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We use a scientific calculator to find the inverse cosine of -0.9041 to find

\theta=154.702^o

Since this angle is not in the required quadrant we must find the other angle who has the same cosine. The required angle is equidistant from the found value from the 180 degrees angle, so our solution is

\theta=180^o+(180^o-154.702)=205.298^o

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