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Vikki [24]
3 years ago
8

The area of triangle B is 25 times greater than the area of triangle A.The perimeter of triangle B is how many times greater tha

n the perimeter of triangle A?
Mathematics
2 answers:
Tpy6a [65]3 years ago
7 0
<span>The ratio of areas is the square of the ratio of perimeters;
The area of triangle B / The area of triangle A = 25 ;
The perimeter of triangle B / The perimeter of triangle A = </span>\sqrt{25} = 5 ;
The perimeter of triangle B is 5many times greater than the perimeter of<span>triangle A!</span>
SVETLANKA909090 [29]3 years ago
3 0
The perimeter of triangle B is 5 times greater than that of A.
The ratio of areas in this example is 1:25.
The ratio of areas is the square of the ratio of perimeters.
\sqrt1 :  \sqrt{25} =1 : 5
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Solve the System using elimination. <br><br> 5x-2y=15<br> 7x+7y=-28
steposvetlana [31]

Answer:

x=1 y=-5

Step-by-step explanation:

7(5x-2y=15) --->      35x-14y=105

2(7x+7y=-28) -->  + <u>14x+14y=-56</u>

                               49x=49  --->x=1

5(1)-2y=15 ---> 5-2y=15 ---> -2y=10 ---> y=-5

8 0
3 years ago
The angles of a quadrilateral measures 80 degrees 100 degrees 100 degrees in this order. What kind of quadrilateral has this sha
bija089 [108]
A parallelogram

Because...
-opposite angles are congruent
-four sides
-angles must equal 360
       100 + 100 +80 + y = 360

       280 + y = 360

       y = 80
-the angle we don't know is 80 degrees


8 0
3 years ago
The locations:
GREYUIT [131]

The quadrilateral is a trapezoid and the area of the quadrilateral is 85.04 square units

<h3>How to determine the quadrilateral?</h3>

The vertices are given as:

A:(-2, 3) B:(4, -6) C:(10, 2) D:(6, 8)

Next, we plot the vertices (see attachment)

From the attached graph, we can see that the quadrilateral is a trapezoid

<h3>How to determine the area?</h3>

From the plot, we have the following features:

Height: AD

Parallel sides: CD and AB

Calculate the lengths using:

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

So, we have:

AD = \sqrt{(-2 -6)^2 + (3 -8)^2}

AD = \sqrt{89}

CD = \sqrt{(10 -6)^2 + (2 -8)^2}

CD = \sqrt{52}

AB = \sqrt{(-2 -4)^2 + (3 +6)^2}

AB = \sqrt{117}

The area is then calculated as:

Area = 0.5 * (CD + AB) * AD

This gives

Area = 0.5 * (√52 + √117) * √89

Evaluate

Area = 85.04

Hence, the area of the quadrilateral is 85.04 square units

Read more about areas at:

brainly.com/question/24487155

#SPJ1

7 0
2 years ago
A flower bed is in the shape of a triangle with one side twice the length of the shortest side and the third side is 14 feet mor
miv72 [106K]

Answer:

onii chan zani moto veno . sain culoco naiso

Step-by-step explanation:zani nqqa quasetni onii san 4

6 0
3 years ago
Plz dont skip and answer. Will give branliest. No links please
Aneli [31]

Answer:

181 mi^2

Step-by-step explanation:

Dimensions of large rectangle, on the left, are 6 mi by 8 m; area is 48 m^2;

Dimensions of small rectangle, in the middle of the diagram, are 4 mi by 5 mi, or 20 mi^2; area is 20 mi^2.

Dimensions of circle:  r = 12 mi; area of quarter circle is (1/4)(3.14)(12 mi)^2, or 113 mi^2.

Total area is 113 mi^2 + 20 mi^2 + 48 mi^2, or 181 mi^2

4 0
3 years ago
Read 2 more answers
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