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jekas [21]
3 years ago
8

If you roll a die three times, how many different sequences are possible?

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
8 0
Work:
There are six faces to a die.
Three sequences.
6*3=18.

The answer is eighteen different sequences.
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3 years ago
Solve. x 2 −5x−8=0 x2−5x−8=0 Enter your answers, as exact values, in the boxes. x = or x =
Sidana [21]

Answer:

x2-5x-8=0  

Step-by-step explanation:

Two solutions were found :

x =(5-√57)/2=-1.275

x =(5+√57)/2= 6.275

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  

Step by step solution :

Step  1  :

Trying to factor by splitting the middle term

1.1     Factoring  x2-5x-8  

The first term is,  x2  its coefficient is  1 .

The middle term is,  -5x  its coefficient is  -5 .

The last term, "the constant", is  -8  

Step-1 : Multiply the coefficient of the first term by the constant   1 • -8 = -8  

Step-2 : Find two factors of  -8  whose sum equals the coefficient of the middle term, which is   -5 .

    -8 + 1 = -7  

    -4+  2 = -2  

    -2+  4 = 2  

    -1 +   8 = 7  

5 0
3 years ago
Read 2 more answers
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