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galina1969 [7]
3 years ago
13

Priya rewrites the expression 8y - 24 as 8(y - 3). Han rewrites 8y - 24 as 2 (4y - 12). Are Priya's and Han's expressions each e

quivalent to 8y - 24? Explain your reasoning
Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

They are equivalent

Step-by-step explanation:

Priya rewrites the expression 8y - 24 as 8(y - 3).

Han rewrites 8y - 24 as 2(4y - 12)

The two expressions are equivalent. This is reached by taking note of the fact that if the factorized form is expanded, they both give the same result.

In Priya's Version,

8(y - 3)=(8 X y)-(8 X 3)=8y-24

Likewise In Han's Version

2(4y - 12)=(2 X 4y) - (2 X 12) =8y-24

We can see from the bolded that our results are the same. Priya's Version is a fully factorized form while Han's Version can still be factorized further to get Priya's version.

i.e. 2(4y - 12)=2 X 4(y-3)=8(y-3)

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Use cosine to find the missing value round to 2 decimal places #trigonometry
Naddika [18.5K]

Answer:

1. 17.27 cm

2. 19.32 cm

3. 24.07°

4. 36.87°

Step-by-step explanation:

1. Determination of the value of x.

Angle θ = 46°

Adjacent = 12 cm

Hypothenus = x

Using cosine ratio, the value of x can be obtained as follow:

Cos θ = Adjacent /Hypothenus

Cos 46 = 12/x

Cross multiply

x × Cos 46 = 12

Divide both side by Cos 46

x = 12/Cos 46

x = 17.27 cm

2. Determination of the value of x.

Angle θ = 42°

Adjacent = x

Hypothenus = 26 cm

Using cosine ratio, the value of x can be obtained as follow:

Cos θ = Adjacent /Hypothenus

Cos 42 = x/26

Cross multiply

x = 26 × Cos 42

x = 19.32 cm

3. Determination of angle θ

Adjacent = 21 cm

Hypothenus = 23 cm

Angle θ =?

Using cosine ratio, the value of θ can be obtained as follow:

Cos θ = Adjacent /Hypothenus

Cos θ = 21/23

Take the inverse of Cos

θ = Cos¯¹(21/23)

θ = 24.07°

4. Determination of angle θ

Adjacent = 12 cm

Hypothenus = 15cm

Angle θ =?

Using cosine ratio, the value of θ can be obtained as follow:

Cos θ = Adjacent /Hypothenus

Cos θ = 12/15

Take the inverse of Cos

θ = Cos¯¹(12/15)

θ = 36.87°

8 0
3 years ago
Suppose that a box contains 7 cameras and that 5 of them are defective. A sample of 2 cameras is selected at random without repl
irinina [24]

Answer:

E(x) = 1.43 (Approx)

Step-by-step explanation:

Given:

Total number of camera = 7

Defective camera = 5

Sample selected = 2

Computation:

when x = 0

P(x=0) = 2/7 × 1/6 = 2/42

P(x=1) = [2/7 × 5/6] + [5/7 × 2/6] = 20/42

P(x=2) = 5/7 × 4/6 = 20/42

So,

E(x) = [0×2/42] + [1×20/42] + [2×20/42]

E(x) = 1.43 (Approx)

8 0
3 years ago
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Answer:

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Answer:

14

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