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galina1969 [7]
3 years ago
13

Priya rewrites the expression 8y - 24 as 8(y - 3). Han rewrites 8y - 24 as 2 (4y - 12). Are Priya's and Han's expressions each e

quivalent to 8y - 24? Explain your reasoning
Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

They are equivalent

Step-by-step explanation:

Priya rewrites the expression 8y - 24 as 8(y - 3).

Han rewrites 8y - 24 as 2(4y - 12)

The two expressions are equivalent. This is reached by taking note of the fact that if the factorized form is expanded, they both give the same result.

In Priya's Version,

8(y - 3)=(8 X y)-(8 X 3)=8y-24

Likewise In Han's Version

2(4y - 12)=(2 X 4y) - (2 X 12) =8y-24

We can see from the bolded that our results are the same. Priya's Version is a fully factorized form while Han's Version can still be factorized further to get Priya's version.

i.e. 2(4y - 12)=2 X 4(y-3)=8(y-3)

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ANSWER and EXPLANATION

We want to order the functions from widest to narrowest:

\begin{gathered} y=3x^2 \\ y=2x^2 \\ y=4x^2 \end{gathered}

To do this, we have to plot the graphs of the functions by using a table of values.

Let us find the values of the functions for values of x = -2, 0, 2

For the first function:

\begin{gathered} y=3x^2 \\ \Rightarrow x=-2: \\ y=3(-2)^2=3*4 \\ y=12 \\ \Rightarrow x=0: \\ y=3(0)^2=3*0 \\ y=0 \\ \Rightarrow x=2: \\ y=3(2)^2=3*4 \\ y=12 \end{gathered}

Hence, its table is:

For the second function:

\begin{gathered} y=2x^2 \\ \Rightarrow x=-2: \\ y=2(-2)^2=2*4 \\ y=8 \\ \Rightarrow x=0: \\ y=2(0)^2=2*0 \\ y=0 \\ \Rightarrow x=2: \\ y=2(2)^2=2*4 \\ y=8 \end{gathered}

Hence, its table is:

For the third function:

\begin{gathered} y=4x^2 \\ \Rightarrow x=-2: \\ y=4\left(-2\right)^2=4*4 \\ y=16 \\ \Rightarrow x=0: \\ y=4(0)^2=4*0 \\ y=0 \\ \Rightarrow x=2: \\ y=4(2)^2=4*4 \\ y=16 \end{gathered}

Hence, its table is:

Now, let us plot the graphs of the functions:

Therefore, from the graph, we see that the order of the functions from widest to narrowest is:

y=2x^2;y=3x^2;y=4x^2

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