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4 years ago

What is 7.4 rounded to the nearest tenth?

Mathematics

2 answers:

stepan [7]4 years ago

8 0

7.4 rounded to the nearest tenth is 7

jolli1 [7]4 years ago

4 0

You can not round it to the nearest tenth because the decimal ends at the tenths place

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3 years ago

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4 years ago

Find Vertical Asymptote(s) for y= (4x^2 +1) / (x^2 -1)

Novay_Z [31]

Answer:

Vertical asymptotes are at $x=-1\ and\ x=1$ .

Step-by-step explanation:

The rational function is given as:

$y=\frac{4x^2+1}{x^2-1}$

Vertical asymptotes are those values of $x$ for which the function is undefined or the graph moves towards infinity.

For a rational function, the vertical asymptotes can be determined by equating the denominator equal to zero and finding the values of $x$ .

Here, the denominator is $x^2-1$

Setting the denominator equal to zero, we get

$x^2-1=0\\x^2=1\\x=\pm \sqrt{1}\\ x= -1\ and\ x = 1$

Therefore, the vertical asymptotes occur at $x=-1\ and\ x=1$ .

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3 years ago