The first diagram below shows a circle with a radius of 1 (unit circle). The circle is drawn on a Cartesian graph with (0,0) as the center of the circle.
From the second diagram, we can determine the value of sin(Θ) = y
and cos(Θ) = x
We can further deduce that
tan(Θ) =
sec(Θ) =
=
cosec(Θ) =
=
cot(Θ) =
=
9514 1404 393
Answer:
B They are similar, but not congruent.
Step-by-step explanation:
Reflection, rotation, and translation are "rigid" transformations. They result in congruent figures.
Dilation is not a rigid transformation. For any dilation scale factor other than 1, the figures will be different sizes, so will not be congruent. They will be similar. (Angles will be congruent, and lines/sides will be parallel.)
The combination of dilation (by 0.5) and reflection results in similar, but not congruent, figures.
legs of the triangles
Each triangle 30-60-90 is:
one leg: 15 ft => short diagonal = 2 * 15ft = 30ft
other leg, x:
tan(30) = 15 / x => x = 15 ft / tan(30) = 25.98 ft
=> long diagonal = 2 * 25.98ft = 51.96 ft
side of the rhoumbus = hypotenuse of one triangle
side of the rhombus = √ [ (15)^2 + (25.98)^2 ] = √(900) = 30 ft
Area of the rhombus:
4 * area of one triangle = 4 [base*height/2] = 4*15*25.98/2 = 779.43 ft^2
The shortest distance accross the garden is equal to the side of the rhombus = 30 ft
Answer:
4 - 5 = 40 books about travel. 80 are school stories.
6-7 = 30 are about nature. 48
8 =24
9 = 18
10 = 2001
Step-by-step explanation:
<h3>4,5,6,7,8</h3>
1/10 = 24 = sport
1/8 = 30 =nature
1/6= 40 =travel
1/5 = 48 = adventure
1/3 = 80 = schools stories
To get that you just have to read the question, find the fractions, percentages etc.
I put them all into fractions and divide 240 by the denominator.
<h3>9</h3>
For question 9, you just have to add all of the amounts of books together and take that away from the total amount. In this case it is 240 - 222 = 18
<h3>10</h3>
You just have to write it out.
Answer: QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.
Step-by-step explanation:
Since we have given that
ΔPQS, and ΔSQR,
Consider, ΔPQS,
As we know that " the length opposite to the largest angle is the shortest segment."
So, According to the above statement.
Similarly,
Consider, ΔSQR,
Again applying the above statement, we get that,
Hence, QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.
