Answer:
a) Hence, the probability of this event occurring if, in fact, the DOT's claim is true
= 3/10 = 0.3
Step-by-step explanation:
a) The concept applied here is combinatorics ; nCr = n!/(n - r)!r!
we are told that out of 5bidders, Three of the bidders were large construction conglomerates
and two were small specialty contractors.
selecting two recipients with tree of the bidders were large construction conglomerates 3C2
= 3!/(3-2)!2!
= 3
Similarly, selecting the two small casualty contractor from the total of 5bidders = 5C2
= 5!/(5-2)!2!
= 10
Hence, the probability of this event occurring if, in fact, the DOT's claim is true
= 3/10 = 0.3
b) if DOTs claim is not true ( probability of failure) = 1 - 0.3
= 0.7 , this value implies that the probability 0.3 is largely compatible and a compliment of the 0.7 and as such it is consistent with the DOTs claim that the selection was random.
