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jek_recluse [69]
3 years ago
6

Find the sum of three consecutive odd integers where x is the greatest integer

Mathematics
1 answer:
myrzilka [38]3 years ago
5 0
X + (x − 2) + (x − 4) = ? ;  In which
<span>
x + x </span>− 2 + x − 4 ; 

Combine the "like terms" ; 

  x + x + x = 3x ; 

  − 2 − 4  =  −6 ; 

So we have:  "3x  − 6" as the sum. ;
___________________________
The sum of three consecutive odd integers, in which "x" is the greatest integer;  is:  "3x − 6" .
_____________________________________________
Note:  The three consecutive odd integers, from least to greatest, are:

"(x − 4)" , "(x − 2)" , and "x" .

The sum is:  "(3x  − 6)<span>" .
</span>_____________________________________________
Note:  "(3x  − 6)" factors into:  " 3(x −2)" .

Note that:  " (x − 2) " is the second integer.
______________________________________________
So the sum total, which is:  "(3x  −  6)" ;  is 3 (three) times the value of the second integer; that is, "3 (x − 2)" .
______________________________________________
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A car travels 205 miles while using 5 gallons of gasoline.
oee [108]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
What are RQS and TQS?
yaroslaw [1]

Answer:

m∠RQS = 72°

m∠TQS = 83°

Step-by-step explanation:

m∠RQS +m ∠TQS = m∠RQT

The two angles combine to make a larger angle

So

m∠RQS = (4x - 20)

m∠TQS = (3x + 14)

(4x - 20) + (3x + 14) = 155

Group the Xs and the constants

4x + 3x - 20 + 14 = 155

Combine like terms

7x - 6 = 155

Add 6 to both sides

7x = 161

Divide by 7 on both sides

x = 23

Check:

4(23) - 20 + 3(23) + 14 = 155

92 - 20 + 69 + 14 = 155

155 = 155

But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.

m∠RQS = 4(23) - 20 = 72°

m∠TQS = 3(23) + 14 = 83°

Checking:

72 + 83 = 155

8 0
3 years ago
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