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xxMikexx [17]
3 years ago
7

Which equation represents the line that passes through the points (4, 6) and (−2, −1)?

Mathematics
1 answer:
KatRina [158]3 years ago
8 0

Find the slope first by using rise/run

m=\frac{6-(-1)}{4-(-2)}\\m=\frac{6+1}{4+2}\\m=\frac{7}{6}

y=mx+b\\y=\frac{7}{6}x+b

We need to find the y-intercept. Substituting one of given ordered pairs. I will use (-2,-1).

Substitute x = -2 and y = -1 in the equation.

-1=\frac{7}{6}(-2)+b\\-1=\frac{7}{-3}+b\\-1=-\frac{7}{3}+b\\-1+\frac{7}{3}=b\\b=\frac{4}{3}

Thus the y-intercept is 4/3.

From y = mx+b, the equation is.

y=\frac{7}{6}x+\frac{4}{3}

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-x²-8x-16=0 <br>what is the solutions by solving by quadratic equations ​
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Answer:

x = - 4

Step-by-step explanation:

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- x² - 8x - 16 = 0 ( multiply through by - 1 to clear the leading negative )

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6 0
3 years ago
I don't know to find the answer to 8. Can someone explain to me?
lapo4ka [179]
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.

A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'

B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)

C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)

D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n

_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.

The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
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3 years ago
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B. 9 I think because it looks like it is bisected in the middle to cut into two equal parts. Please correct me if I am wrong. Thanks. 
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I think 5.4

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