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Schach [20]
4 years ago
15

What is 102 divided by 6 in distributive property

Mathematics
1 answer:
Mila [183]4 years ago
4 0
The answer to <span>102 divided by 6 in distributive property would have to be </span>17
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Please help me someone!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
const2013 [10]
Split the second term in
2x squared -5x + 3 into two terms
2x squared - 2x - 3x + 3
Factor out common terms and last two terms
2x(x-1) -3 (x-1)
Factor out the common term x - 1
ANSWER: (x-1) (2x-3)
5 0
3 years ago
(4x+1)(3x-7) yup it hurts
musickatia [10]

Answer:

12x^2-25x-7

Step-by-step explanation:

Multiply each term by its counterpart in the parenthesis.

4x*3x and 4x*-7

1*3x and 1*-7

This gives you 12x^2-4x*7+3x-7 when the like terms are combined.

Collect the like terms, which will give you 12x^2-25x-7

7 0
3 years ago
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5. Tanya made a deposit of $150 into her
xenn [34]
She now has $300 in her account
5 0
3 years ago
Read 2 more answers
Jim washes 2/3 of his car with 1/2 a bottle of soap. What fraction of the soap will he use to clean his entire car?​
Sunny_sXe [5.5K]

Answer:

if he uses 1/2 for 2/3, then you can divide 2/3 and 1.2 by 2 to get the remaining soap needed to complete the wash

so to clean the last 1/3 of the car, he`ll use 1/4 of the remaining soap

the entire car needs <u><em>3/4 of a bottle of soap</em></u>

3 0
3 years ago
What situation should be used to rewrite 16(x^3+1)^2 -22(x^3+1)-3=0 as a quadratic equation
Oliga [24]
16(x^3+1)^2-22(x^3+1)-3=0

Use substitution:  x^3+1=t

16t^2-22t-3=0\\\\16t^2-24t+2t-3=0\\\\8t(2t-3)+1(2t-3)=0\\\\(2t-3)(8t+1)=0\iff2t-3=0\ \vee\ 8t+1=0

2t-3=0\ \ \ |+3\\\\2t=3\ \ \ |:2\\\\t=\dfrac{3}{2}\\..............................\\8t+1=0\ \ \ \ |-1\\\\8t=-1\ \ \ \ |:8\\\\t=-\dfrac{1}{8}

we're going back to substitution:

x^3+1=\dfrac{3}{2}\ \vee\ x^3+1=-\dfrac{1}{8}\ \ \ \ |subtract\ 1\ from\ both\ sides\ of\ the\ equations\\\\x^3=\dfrac{1}{2}\ \vee\ x^3=-\dfrac{9}{8}\\\\x=\sqrt[3]{\dfrac{1}{2}}\ \vee\ x=\sqrt[3]{-\dfrac{9}{8}}


x=\dfrac{1}{\sqrt[3]2}\ \vee\ x=-\dfrac{\sqrt[3]9}{2}\\\\\boxed{x=\dfrac{\sqrt[3]4}{2}\ \vee\ x=-\dfrac{\sqrt[3]9}{2}}

4 0
3 years ago
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