1/2 = cos(2*t)sqrt(3) /2 = sin(-2*t)find tfind the time derivative of x(t), y(t)(-2sin(2*t) , -2cos(2*t) )plug in the t you found to find the velocity vector.
Answer:
+ 11m - 11
Step-by-step explanation:
6m+(m-2)(m+7)+3 = 6m + [ m*m - 14 -2m + 7m] + 3
= 6m + mm - 14 + 5m + 3
= mm + 11m - 11
6m+(m-2)(m+7)+3 =
+ 11m - 11
Answer:
x=2
Step-by-step explanation:
Solution is attached
You can plug 2 back into the equation to verify :)
Is there a picture or something?