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Scrat [10]
2 years ago
10

Evaluate A2 for A = -3. -9 -6 6 9

Mathematics
2 answers:
elena55 [62]2 years ago
8 0
Ok so basically it is saying substitue when a equals all of those numbers,so basically I will show you.

a (times) 2 = ?   so substitute one of the numbers for a which would be like this its basically multiplication so, (-3) (times) 2 = -6 so that solves one part do the same with the other numbers and that will give you all the answers like so,

(-9) (times) 2 = -18   (-6) (times) 2 = -12    (6) (times) 2 = 12 and finally the last one is (9) (times) 2 = 18 which are all correct answers.

so basically, your answers are gonna be -6,-18,-12,12,18 which are or should be all correct
schepotkina [342]2 years ago
5 0
Evaluate A² for A = -3.

(-3)² = (-3) * (-3) = 9

Your answer is 9.

If the question is, however, evaluate A2, which is 2A, for A = -3, then the answer is:

2A = 2(-3) = -6.
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Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

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in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

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P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

6 0
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Step-by-step explanation:

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