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2 years ago

Evaluate A2 for A = -3. -9 -6 6 9

2 answers:

8 0

Ok so basically it is saying substitue when a equals all of those numbers,so basically I will show you.

a (times) 2 = ? so substitute one of the numbers for a which would be like this its basically multiplication so, (-3) (times) 2 = -6 so that solves one part do the same with the other numbers and that will give you all the answers like so,

(-9) (times) 2 = -18 (-6) (times) 2 = -12 (6) (times) 2 = 12 and finally the last one is (9) (times) 2 = 18 which are all correct answers.

so basically, your answers are gonna be -6,-18,-12,12,18 which are or should be all correct

schepotkina [342]2 years ago

5 0

Evaluate A² for A = -3.

(-3)² = (-3) * (-3) = 9

Your answer is 9.

If the question is, however, evaluate A2, which is 2A, for A = -3, then the answer is:

2A = 2(-3) = -6.

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We are given that a psychologist claims that more than 4.1% of the population suffers from professional problems due to extreme shyness.

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3 years ago

Write an equation for a circle with a diameter that has endpoints at (–10, 1) and (–8, 5). Round to the nearest tenth if necessa

satela [25.4K]

The standard form for the equation of a circle is :

(x−h)^2+(y−k)^2=r2 ----------- EQ(1)
 where handk are the x and y coordinates of the center of the circle and r is the radius.
 The center of the circle is the midpoint of the diameter.

So the midpoint of the diameter with endpoints at (−10,1)and(−8,5) is :

((−10+(−8))/2,(1+5)/2)=(−9,3)

So the point (−9,3) is the center of the circle.

Now, use the distance formula to find the radius of the circle:

r^2=(−10−(−9))^2+(1−3)^2=1+4=5

⇒r=√5

Subtituting h=−9, k=3 and r=√5 into EQ(1) gives :

(x+9)^2+(y−3)^2=5

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3 years ago