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Lerok [7]
2 years ago
10

She works as a waitress at a local Emerald Monday restaurant. Her regular hourly wage is $15.50. She regularly works 40 hours pe

r week. What is her regular weekly pay? If she works 50 weeks each year at this rate, what is her annual salary?
Mathematics
1 answer:
lina2011 [118]2 years ago
8 0

Answer:

Her regular weekly pay is $62 and her annual salary is $3100.

Step-by-step explanation:

Given that her hourly wage=$15.50 / hour

As she works 40 hours per week, so her weekly pay = 15.50 x 40 = $62/ week.

If she works 50 weeks each year, so her yearly pay = 62x50=$3100 /year.

Hence, her regular weekly pay is $62 and her annual salary is $3100.

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3 years ago
Quit smoking: In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.
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Answer:

The p-value of the test is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

Step-by-step explanation:

Test if less than half of HIV-positive smokers have used a nicotine patch:

At the null hypothesis, we test if the proportion is of at least half, that is:

H_0: p \geq 0.5

At the alternative hypothesis, we test if the proportion is below 0.5, that is:

H_1: p < 0.5

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

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In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

This means that n = 444, X = \frac{202}{444} = 0.455

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.455 - 0.5}{\frac{0.5}{\sqrt{444}}}

z = -1.9

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.455, which is the p-value of z = -1.9.

Looking at the z-table, z = -1.9 has a p-value of 0.0287.

The p-value is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

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3 years ago
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N/A

Step-by-step explanation:

What is line AC, was there supposed to be a picture?

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median i think 60

Step-by-step explanation:

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In standard form it would be x + 2y = 8.

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