Question

PLEASE HELP ME I HAVING TROUBLE

Answer 1

Answer: f(-6) = $-\frac{12}{11}$, f(-4) = $\frac{8}{9}$, f(4) = $-\frac{8}{9}$, f(6) = $\frac{12}{11}$

Step-by-step explanation:

(-6, f(-6)) is an x,y coordinate.  They are asking what the y-value is when you plug in -6 for x.

f(x) = $\frac{2x}{x^{2}-25}$

f(-6) = $\frac{2(-6)}{(-6)^{2}-25}$

      = $\frac{-12}{36-25}$

      = $-\frac{12}{11}$

f(-4) = $\frac{2(-4)}{(-4)^{2}-25}$

      = $\frac{-8}{16-25}$

      = $\frac{-8}{-9}$

      = $\frac{8}{9}$

f(4) = $\frac{2(4)}{(4)^{2}-25}$

      = $\frac{8}{16-25}$

      = $\frac{8}{-9}$

      = $-\frac{8}{9}$

f(6) = $\frac{2(6)}{(6)^{2}-25}$

      = $\frac{12}{36-25}$

      = $\frac{12}{11}$