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Ratling [72]
3 years ago
7

9.1(6)+8.7(7)=_+60.9 How do I solve this?

Mathematics
1 answer:
timurjin [86]3 years ago
7 0

Answer:

The answer is <u>54.6</u>.

9.1(6)+8.7(7)=<u>54.6</u>+60.9

Step-by-step explanation:

Given:

9.1(6)+8.7(7)=_+60.9

Now, to solve it:

9.1(6)+8.7(7)=_+60.9

Let the _be x.

So, we remove parenthesis first that makes it multiply with the number next to it:

9.1\times 6+8.7\times 7=x+60.9

54.6+60.9=x+60.9

Now adding on L.H.S:

115.5=x+60.9

Subtracting on both sides by 60.9 we get:

54.6=x

x=54.6

Therefore, the answer is 54.6.

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5. A video game console at Games Galore
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Answer:

$319.60

Step-by-step explanation:

Normal Game console cost : $399.50

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$399.50×0.20= $79.90

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2. Mr. Abdulla has 160 cows, goats, horses, and chickens on his farm. 19% of the animals are cows, 28% are goats, 13% are horses
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Step-by-step explanation:

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3 years ago
Approximate the change in the volume of a sphere when its radius changes from r = 30 ft to r=10.1 ft [v(r)=4/3Ï€r^3]. When r cha
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Answer: ∆V for r = 10.1 to 10ft

∆V = 40πft^3 = 125.7ft^3

Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________

[v(r)=4/3Ï€r^3].

Step-by-step explanation:

Volume of a sphere is given by;

V = 4/3πr^3

Where r is the radius.

Change in Volume with respect to change in radius of a sphere is given by;

dV/dr = 4πr^2

V'(r) = 4πr^2

V'(10) = 400π

V'(10.1) - V'(10) ~= 0.1(400π) = 40π

Therefore change in Volume from r = 10 to 10.1 is

= 40πft^3

Of by direct substitution

∆V = 4/3π(R^3 - r^3)

Where R = 10.1ft and r = 10ft

∆V = 4/3π(10.1^3 - 10^3)

∆V = 40.4π ~= 40πft^3

And for R = 30ft to r = 10.1ft

∆V = 4/3π(30^3 - 10.1^3)

∆V = 34626.3πft^3

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3 years ago
A square postage stamp has area 1,130 mm². About how long is each side?
Anna007 [38]

Answer:

33.61 mm (the square root of 1130)

Step-by-step explanation:

3 0
3 years ago
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