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Ivanshal [37]
3 years ago
7

Tina needs 36 flowers for her next project. The flowers are sold in bunches

Mathematics
1 answer:
natka813 [3]3 years ago
7 0
She will need at least 8 bunches
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Simplify 3(x+7)-2(4x-3)=
Andre45 [30]

Answer:

−5x+27

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab 2. if one addend is –5a2b2 12a2b – 5, what is the other addend? 15a2b2 –
Brrunno [24]

The other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The sum of two polynomials is,

10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2

The one polynomial addend is,

-5a^2b^2 +12a^2b - 5

Let suppose the other polynomial addend is f(a,b). Thus,

(-5a^2b^2 +12a^2b - 5)+f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)

Isolate the second polynomial as,

f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)-(-5a^2b^2 +12a^2b - 5)\\f(a,b)=10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2+5a^2b^2 -12a^2b + 5

Arrange the like terms as,

f(a,b)=10a^2b^2+5a^2b^2 - 8a^2b -12a^2b+ 6ab^2 - 4ab + 2+5\\f(a,b)=15a^2b^2- 20a^2b + 6ab^2 - 4ab + 7

Hence, the other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

Learn more about polynomial here;

brainly.com/question/24380382

7 0
2 years ago
3x + 2 = 11 what is x?
nevsk [136]

Answer:

x = 3

Step-by-step explanation:

3x + 2 = 11

      -2     -2

3x = 9

÷3    ÷3

x = 3

7 0
3 years ago
Read 2 more answers
1. Refer to the equation 2x − 6y = 12. (a) Create a table of values for at least 4 points. Show your work.
Sergio039 [100]
2x - 6y = 12

so we pick any number for x and then solve for y

lets say x = 0
2(0) - 6y = 12
-6y = 12
y = -12/6
y = -2....so when x = 0, y = -2....(0,-2) <== one point

lets say x = 1
2(1) - 6x = 12
2 - 6x = 12
-6x = 12 - 2
-6x = 10
x = -10/6
x = - 5/3...so when x = 1, y = -5/3....(1,-5/3) <== another point

Lets say x = 2
2(2) - 6y = 12
4 - 6y = 12
-6y = 12 - 4
-6y = 8
y = -8/6
y = - 4/3....so when x = 2, y = -4/3.....(2,-4/3) <== another point

lets say x = 3
2(3) - 6y = 12
6 - 6y = 12
-6y = 12 - 6
-6y = 6
y = -6/6
y = -1....so when x = 3, y = -1.....(3,-1) <== another point

now there is 4 points.
4 0
3 years ago
The shaded sector above covers 1/3 of the circle. If the radius of the circle above is 3 cm, what is the area of the sector in t
Mekhanik [1.2K]

Given:

The shaded sector above covers \dfrac{1}{3} of the circle.

Radius of the circle = 3 cm

To find:

The area of the sector in terms of π.

Solution:

The area of a circle is

A=\pi r^2

Substituting r=3, we get

A=\pi (3)^2

A=9\pi

It is given that the shaded sector above covers \dfrac{1}{3} of the circle.

The area of shaded sector =\dfrac{1}{3}A

                                             =\dfrac{1}{3}(9\pi)

                                             =3\pi

Therefore, the area of shaded sector is 3π sq. cm.

5 0
3 years ago
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