Answer: 81%
Step-by-step explanation:
From the question, we are informed that a student received the following test scores: 71%, 89%, 72%,
84% and 83% in 5 tests and the student wants to maintain an average of 80%.
The lowest score/grade they can receive on the next test to maintain at least an 80% average first thus:
First, to make it easy we can remove the percent sign. Then we multiply 80 by 6 since we're calculating for 6 tests scores. This will be:
= 80 × 6
= 480
We then add all the 5 test scores. This will be:
= 71 + 89 + 72 + 84 + 83
= 399
We then subtract the values gotten. This will be:
= 480 - 399
= 81
This means the student must get at least 81%
Answer:
4√2x.
Step-by-step explanation:
√32 = √2*√16 = 4√2.
√x^2 = x.
If you are taking one away from the other the answer is 50 degrees so try that hope this helps
=C.
Um, we see that the slice created the triangle, and the formula to find the area of the triangle:
1/2×B×h where B represent Base and h represent height.
In this case, Base=5 cm
Height=11 cm
A=1/2×11×5
A=5.5×5
A=27.5 square cm. As a result, the area of the resulting two-dimensional cross section is 27.5 square cm. Hope it help!
X/2-y/3=3/2
(6×x/2)-(6×y/3)=6×3/2
3x-2y=9______(1)
x/3+y/2=16/3
(6×x/3)+(6×y/2)=6×16/3
2x+3y=32_____(2)
(1)×3____9x-6y=27____(3)
(2)×2____4x+6y=64____(4)
(3)+(4)___13x=91
x=7
3(7)-2y=9
-2y=-12
y=6
