Rewrite the expression...see attached picture....
2 answers:
For this case we must take into account the following properties of exponents:
1) Same base, the exponents are added
2) The addition and subtraction of polynomials can only be done between terms of the same degree.
3) r (x) is the residue
4) q (x) is the quotient
5) b (x) is the divisor
Answer:
See attached image.
1) Same base, the exponents are added
2) The addition and subtraction of polynomials can only be done between terms of the same degree.
3) r (x) is the residue
4) q (x) is the quotient
5) b (x) is the divisor
Answer:
See attached image.
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Answer:
1st problem: b)
2nd problem: c)
Step-by-step explanation:
1st problem:
The formula/equation you want to use is:
where
t=number of years
A=amount he will owe in t years
P=principal (initial amount)
r=rate
n=number of times the interest is compounded per year t.
We are given:
P=2500
r=12%=.12
n=12 (since there are 12 months in a year and the interest is being compounded per month)
Time to clean up the inside of the ( ).
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2nd Problem:
Compounded continuously problems use base as e.
P is still the principal
r is still the rate
t is still the number of years
A is still the amount.
You are given:
P=2500
r=12%=.12
Let's plug that information in:
.