1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KonstantinChe [14]
3 years ago
13

A wildlife habitat houses 41 animals. There are three more reptiles than mammals in the habitat. There are seven fewer amphibian

s than mammals in the habitat. How many amphibians are there in the habitat?
Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer: 8

Step-by-step explanation:

Let mammals be represented by y

There are three more reptiles than mammals in the habitat. Therefore, Reptiles = y + 3

There are seven fewer amphibians than mammals in the habitat. Therefore, amphibian = y - 7

y + y + 3 + y - 7 = 41

3y - 4 = 41

3y = 41 + 4

3y = 45

y = 45/3

y = 15

Since amphibian = y - 7

= 15 - 7

= 8

There are 8 amphibians

You might be interested in
Part 1: Record Information Spend a short amount of time (one to five minutes) doing your activity. Answer the following question
gizmo_the_mogwai [7]

Answer:

I think your gonna have to do this one on your own because this is a whole experiment. Just saying. :)

Step-by-step explanation:

7 0
2 years ago
Travis sketches a scale drawing of his favorite race car. The scale he uses is 1 centimeter equals 1/4 foot. If the length of th
kirill [66]
16 because 1=  1 x 1/4 foot so 64= 64 x 1/4 foot
4 0
3 years ago
Read 2 more answers
An estimated regression equation that was fit to estimate ductility in steel using its carbon content was found to be significan
AnnZ [28]

Answer:

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

Step-by-step explanation:

Hello!

Considering the dependent variable:

Y: Ductility in steel.

And the independent variable:

X: Carbon content of the steel.

The linear regression was estimated and a prediction interval was calculated.

The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=x_{0}]

In this case 95% prediction interval for Y/X=0.5

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

I hope it helps!

6 0
3 years ago
Yall someone help I still have a bunch if other test and I'm so tired ;-;
g100num [7]

Me das mas información?

6 0
2 years ago
Find the values of a and b that make f continuous everywhere. f(x) = x^2 − 4 / x − 2 if x < 2 ax^2 − bx + 3 if 2 ≤ x < 3 4
inysia [295]
<span>Find the values of a and b that make f continuous everywhere. f(x) = x^2 − 4 / x − 2 if x < 2 ax^2 − bx + 3 if 2 ≤ x < 3 4x − a + b if x ≥ 3 </span>
a=7/12
b=13/2

4 0
3 years ago
Other questions:
  • What is the area of this polygon?<br><br><br><br> Enter your answer in the box.<br><br><br> units²
    15·2 answers
  • What else would need to be congruent to show that triangle ABC is congruent to triangle DEF by ASA?
    10·2 answers
  • Rewrite 8^6 • 8^4 in the form 8^n
    5·2 answers
  • when xena says a number yoli tripples the number. make a table that shows three pairs of numbers xena and yoli might say.
    11·1 answer
  • Graph the line whose y-intercept is - 4 and whose x-intercept is -2.
    8·1 answer
  • From 45 quarts to 8 quarts​
    7·2 answers
  • If y varies jointly as x and z and y = 24 when x = 2 and z = 1, find y when x is 12 and z is 2.
    7·1 answer
  • Y’all someone help pls 5x-3=21-x
    13·2 answers
  • A worker is paid Rs. 2600 for 21 days work. If his total income of the month is Rs. 2400, for how many days he didn't work? I ne
    12·1 answer
  • How do you do question 5 I was out sick and it is due tomorrow I need help. Please.​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!