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KonstantinChe [14]
3 years ago
13

A wildlife habitat houses 41 animals. There are three more reptiles than mammals in the habitat. There are seven fewer amphibian

s than mammals in the habitat. How many amphibians are there in the habitat?
Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer: 8

Step-by-step explanation:

Let mammals be represented by y

There are three more reptiles than mammals in the habitat. Therefore, Reptiles = y + 3

There are seven fewer amphibians than mammals in the habitat. Therefore, amphibian = y - 7

y + y + 3 + y - 7 = 41

3y - 4 = 41

3y = 41 + 4

3y = 45

y = 45/3

y = 15

Since amphibian = y - 7

= 15 - 7

= 8

There are 8 amphibians

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3 0
3 years ago
The scores on an achievement test are normaly distributed with mean µ = 100 and standard deviation σ = 100. What should the scor
ser-zykov [4K]

Answer:

the student should score atleast 229 to be among the top 10%.

Step-by-step explanation:

in terms of the normal distribution, and if the table that you're using calculates the area of the normal distribution from the mean to a point x, only then what we are actually finding the value 'x' at which the z-score is at 40% (the rest 50% is already skipped by the table)

P(0.4) = \dfrac{x - \mu}{\sigma}

after finding the the value at this z-score, we can find the value of x at which the score is in the top 10% range.

we can find the z-score either using a normal distribution table or calculator. (but be sure what area is it calculating)

looking at the table the closest value we can find is, 0.4015 at z = 1.29 ((it is above 40% because we want to be in the top 10% range)

P(0.4015) = \dfrac{x - 100}{100}

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x = 1.29(100) + 100

x = 229

the student should score atleast 229 to be among the top 10%.

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