Step-by-step explanation:
Hey there!!!
Here,
Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.
The equation of a straight line passing through point is,

Now, put all values.

It is the 1st equation.
Another equation is;
y = 5x +2........(2nd equation).
Now, Comparing it with y = mx + c, we get;
m2=5
As per the condition of perpendicular lines,
m1×m2= -1
m1 × 5 = -1
Therefore, m2= -1/5.
Keeping the value of m1 in 1st equation.

Simplify them.



Therefore the required equation is x+5y+8= 0.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Since this is a linear function, filling in the minimum and maximum of the domain is sufficient.
f(-4) = -16 + 9 = -7
f(2)= 8 + 9 = 17
So the range of the function (given the domain) :
R = {-7, 17}
Answer:
should be 192
Step-by-step explanation:
A point that is half way of line segment is the midpoint
Let (6, 7) be (x₁, y₁) and (-7, -6) be (x₂, y₂)
Mid point of HI = (

)
Mid point of HI = (

Mid point of HI = (

)
Santiago's statement is not correct
Step-by-step explanation:
Hi, I think correct variant is B
(28÷7)+7=4+7=11