Question

The elevation E, in meters, above sea level at which the boiling point of a certain liquid is t degrees Celsius is given by the function shown below. At what elevation is the boiling point 119.5? 120? E(t)= 1200(120-t)+520(120-t)^2 At what elevation is the boiling point 119.5?
E(119.5)= (the answer) meters

Answer 1

Answer:

$E(119.5)= 730m$

Step-by-step explanation:

Given

$E(t)= 1200(120-t)+520(120-t)^2$

Required

Determine E(119.5)

$E(t)= 1200(120-t)+520(120-t)^2$

Simply substitute 119.5 for t

$E(119.5)= 1200(120-119.5)+520(120-119.5)^2$

Evaluate the expressions in bracket

$E(119.5)= 1200(0.5)+520(0.5)^2$

Solve 0.5²

$E(119.5)= 1200 * 0.5+520*0.25$

$E(119.5)= 600+130$

$E(119.5)= 730$

Hence;

$E(119.5)= 730m$