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alexandr402 [8]
3 years ago
12

Sea level is measured over a 20 year period. The graph shows the number of years since the study began and the corresponding cha

nge in sea level.
Which statement best describes the rate of change for the situation?
A. The height of the water increases 0.3 cm per year.
B. The height of the water increases 1.5 cm per year.
C. The height of the water increases 2 cm per year.
D. The height of the water increases 6 cm per year.
Mathematics
1 answer:
Ugo [173]3 years ago
4 0

Answer:

The Answer is A. The height of the water increases 0.3cm per year. I Just took the Quiz and And got it correct

Step-by-step explanation:

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What is -2(5+6m) + 16 = -90 ?<br> Can you please show with detail
GarryVolchara [31]

Answer:

m = 8

Step-by-step explanation:

-2(5 + 6m) + 16 = -90

Start by distributing -2 inside the parentheses. This means you will multiply everything inside the parentheses (5 + 6m) by -2.

-10 - 12m + 16 = -90

Simplify the left side of the equation by combining like terms.

6 - 12m = -90

Subtract 6 from both sides of the equation to isolate the term containing the variable m and to move all other terms to the other side (right) of the equation.

-12m = -96

Divide both sides of the equation by -12 to isolate and solve for m.

m = 8

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3 years ago
Find the circumference of the object. Use $3.14$ or $\frac{22}{7}$
TiliK225 [7]
C≈6.28m your welcome
4 0
3 years ago
Which weights more 2.48 or 2.5​
Mazyrski [523]
2.5 weighs more. It’s a greater number than 2.48
6 0
2 years ago
A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. ​(a) Describe the
Ivanshal [37]

Answer:

a) \bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

b) z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

c) z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

d) z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

\mu = 83, \sigma = 27

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

Part b

We want this probability:

P(\bar X>89)

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 89 we got:

z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

Part c

P(\bar X

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 75.65 we got:

z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

Part d

We want this probability:

P(79.4 < \bar X < 89.3)

We find the z scores:

z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

8 0
3 years ago
3 times a number xx, subtracted from 1818, is less than -90.?90. Write an inequality for the statement above. Find the solution
Evgen [1.6K]

Answer:

The solution set is: x>36

Step-by-step explanation:

We are given that we have to subtract 3 times of some number 'x' from 18 such that the resulting equation is less than -90.

this means that : 18-3x<-90

on solving the inequality by adding 3x on both side and adding 90 on both side we get that

 108<3x

now on dividing both side by 3 we get that

x>36

Hence our solution set is: x>36


5 0
3 years ago
Read 2 more answers
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