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iogann1982 [59]
3 years ago
5

What is the slope of the line that contains the points (-1, -1) and (3, 15)?

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0
To get slope (m), use the equation
m = (y2 - y1)/(x2 - x1)

Then plug in the points
m = (15 + 1)/(3 + 1)
m = (16)/(4)
m = 4

answer is A. 4
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A line passes through the points (-1, -6) and (-4, 3). What is the equation of this line in slope-intercept form?
g100num [7]

Since we have two ordered pairs, we can find the slope by plugging them into (y2-y1)/(x2-x1) which translates to (3-(-6))/(-4-(-1))=9/-3=-3

Since the slope is -3, we have the equation y=-3x+b, but we don't know b. So we plug in values for x and y and solve for b.

-6=-3(-1)+b

-6=3+b

-9=b

So the y-intercept is -9 and the full equation is y=-3x-9 which means A is the only correct answer.

Hope this helped!

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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Explanation:

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For something like x = 2.5 or x = 2.7, the value of \lfloor x \rfloor will be 2. It doesn't matter that 2.7 is closer to 3 than it is to 2. The interval 2 \le x < 3 will be entirely on the x axis since we are taking the result of the flooring operation and subtracting off 2. Notice how x = 3 is not included. This is because x = 3 leads to y = 1 instead of y = 0. So we have an open hole at the end of the interval. The same goes for any other piece as well.

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