Partial would be the answer your looking for
I can’t see the image, can you name some of the energy resources under this comment?
Here we have to explain and get the product of the reaction between 3-methyl-1,3-diol and chromium-tri-oxide (CrO₃)
The reaction between 3-methyl-1,3-diol with chromium-tri-oxide (CrO₃) form 3-methyl-3-hydroxybutanal.
The CrO₃ is used as a mild oxidant to the alcohol. It only produces aldehyde or ketone depending upon the position of the -OH group in a secondary or primary alcohol.
Here we can see there are two hydroxy (-OH) group in the reactant. However one of the hydroxy is at terminal carbon atom, thus primary alcohol and other in between as tertiary alcohol.
As the reagent CrO₃ does not reacts on the tertiary -OH group thus the -OH group present at 3 position will not be oxidized. Thus only the terminal hydroxy group will oxidize to form the corresponding aldehyde.
Henceforth the final product of the reaction is 3-methyl-3-hydroxybutanal as shown in the figure.
The amount of energy required to remove the most loosely bound electron in1 mole of an atom in its neutral gaseous state. Atomic radius is smaller, great nuclear charge (pulling power of protons on less electrons)