Answer is: adding NaCl will lower the freezing point of a solution.
A solution (in this example solution of sodium chloride) freezes at a lower temperature than does the pure solvent (deionized water).
The higher the solute concentration (sodium chloride), freezing point depression of the solution will be greater.
Equation describing the change in freezing point:
ΔT = Kf · b · i.
ΔT - temperature change from pure solvent to solution.
Kf - the molal freezing point depression constant.
b - molality (moles of solute per kilogram of solvent).
i - Van’t Hoff Factor.
Dissociation of sodium chloride in water: NaCl(aq) → Na⁺(aq) + Cl⁻(aq).
Answer:
one mole of carbon would have a mass of 12.011 grams
Answer:
The correct answer is 117.68 g
Explanation:
In order to calculate the mass the chemist has to weigh, we have to multiply the concentration of the solution (0.200 M) by the volume (2.00 L). As the concentration is given in M (mol/L) we first have to convert the concentration from molarity to g/L by using the molecular weight of K₂Cr₂O₇.
From the Periodic Table we know the molar mass (MM) of the constituting elements K, Cr and O:
molecular weight K₂Cr₂O₇= (2 x MM K) + ( 2 x MM Cr) + (7 x MM O)
molecular weight K₂Cr₂O₇= (2 x 39.1 g/mol) + ( 2 x 52 g/mol) + ( 7+ 16 g/mol)
molecular weight K₂Cr₂O₇= 294.2 g/mol
Finally, we can calculate the mass as follows:
mass= 0.200 mol/L x 294.2 g/mol x 2.00 L= 117.68 g
Answer:
38.5 L
Explanation:
For this question, we can use
V1/T1=V2/T2
where
V1 (initial volume)= 35 L
T1 (initial temperature in Kelvin)= 303 K
V2(final volume)= ?
T2 (final temperature in Kelvin)= 333K
Since we are trying to find the final volume, we can rearrange the equation to say
V2= (V1/T1) × T2
V2= (35/303)×333
V2= 38.5 L